Solve using Gaussian Elimination with back-substitution or Gauss Jordan 5x1 + 2x2 + X3 = 0 2x1 + x2 = 3 O ¤1 = -2, x2 = 4, x3 = 2 %3D %3D O x1 = -1, 22 = 2, x3 =1 %3D %3D O 1 = -7, x2 = 14, x3 = 7 O All of the choices

Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter11: Matrices And Determinants
Section11.CT: Chapter Test
Problem 6CT
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Solve using Gaussian Elimination with back-substitution or Gauss Jordan
51 + 2x2 + x3 = 0
2x1 + x2
=D3
O *1 = -2, x2 = 4, xz = 2
O ¤1 = -1, x2 = 2, x3 = 1
O *1 = -7, x2 = 14, *3 = 7
O All of the choices
Transcribed Image Text:Solve using Gaussian Elimination with back-substitution or Gauss Jordan 51 + 2x2 + x3 = 0 2x1 + x2 =D3 O *1 = -2, x2 = 4, xz = 2 O ¤1 = -1, x2 = 2, x3 = 1 O *1 = -7, x2 = 14, *3 = 7 O All of the choices
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