Solve xdy + (3x – 2y)dx = 0 in two ways. 1. First Method

Q: II. Solve xdy + (3x – 2y)dx = 0 in two ways. 1. First Method 2. Second Method

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Q: (y + 1)dx + (4x – y)dy = 0

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Q: Solve the equation dy 2 dx with the initial condition y (1) = 1. 2/3

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Q: 1 Evalute: dx (x'+2x+2)'

A: Please refer the attached image for complete solution.

Q: (Think Bernoulli) Solve implicitly dy dx - y = e²xy³

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Q: Solve the initial value problem 2(y– 1)dy = (4x2 + 5x - 1)dx for y(0) = 2 %3D

A: 2(y — 1)dy = (4x2 + 5x — 1)dx This differential equation is in the form of variable separable.

Q: dx ex -1

A: Let ex=t ⇒exdx=dt    dx=dtex          =dtt

Q: Solve for the general solution (4ху +3у — х) dx +x (x+2у) dy %3D 0

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Q: solve DE (3xy+y2)dx +(x2+xy)dy=0

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Q: Solve the initial value problem. √y dx + (x-4)dy=0, y(5)= 36

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Q: Solve 4 x*dy +y*dx = 0

A: The given differential equation is: x4dy+y4dx=0x4dy=-y4dxdyy4=-dxx4

Q: Solve the following DE. 13. (5x + 3 e) dx + 2x e' dy = 0. 14. (3x + y-2) dx + (3x +y+4) dy = 0. 15.…

A: Given that: (5x+3ey)dx+2xeydy=0     NOTE: As per our answering guidelines, we can only answer 1…

Q: Solve bernoulli equation (dy)/(dx) - y = x * y ^ 2

A: Given problem:- Solve bernoulli equation (dy)/(dx) - y = xy2

Q: (x² + y²)dx – xy dy = 0

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Q: Obtain the general solution to the equation. dy 1. y + 2x + 1 dx

A: Given that: dydx=yx+2x+1

Q: Solve the initial value problem. dy + 9xy = 4x, y(0) = - 3 dx

A: This question is related to differential equations, we will solve it using given information.

Q: 4. Using homogenous D.E approach, solve (x³ – 3xy?)dx = (y3 – 3x²y)dy.

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Q: dy -y² = yx+x² dx

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Q: Solve th D.E using Exact (6x² – y +3)dx+(3y – x – 2)dy

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Q: Solve the initial value problem dy/dx=2x−1x2, x≠0, y(1)=5.

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Q: 5) SOLVE dy 2 y (1) == (ive) dx 2

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Q: 6. Solve (2xy*e" + 2xy³ + y)dx + (x²y*ev – x?y² – 3x)dy = 0. -

A: Since you have asked multiple question, as per company guidelines we will solve the first question…

Q: 1. Solve the equation 3(y+1)dx-(x+y+3)dy =0.

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Q: Solve the equation (4y + 2x – 5 dx + (6 y + 4x – 1 dy = 0 subject to the initial condition y(-1)= 2.…

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Q: Solve the initial value problem: dy 8 y(8) = –9 » dx x – 7 |

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Q: A. Solve dy (1+x+) dx

A: We have to find the solution

Q: Find the general solution  ytan2x dx + ln4 ydy = 0

A: We will use variable separable form to find the general solution of the differential equation.

Q: 4x − 5y + 3)dx − (2x − 3y − 1)dy = 0 how solve this problem?

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Q: 2. Solve the DE: (2x + dx + 2y ) dy = 0 1+ x?y? 1+ x?y?

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Q: Solve by finding an integrating factor (xy² + y)dx – xdy = 0

A: xy2+ydx-x dy=0

Q: dy 1. Solve 2y - e dx

A: Given differential equation is dydx=2y-e3x. To find the solution. Solution: Given differential…

Q: The solution of (1 – y² )dx + (1 + x² )dy = 0 is:

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Q: solve 2 x d zy dx=

A: Given: The second order differential equation is x2d2ydx2+4xdydx+2+xy=0

Q: Solve the initial value problem dy/dx=x2−1, y(3)=7.

A: Given:

Q: (ve* +y)dx+(2xye* +1)dy = 0

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Q: Solve the initial value problem: dy/dx= (1/(2sqrt(x)))+2 y(1)=3

A: Solving the initial value problem.

Q: Solve dy/dx−6y=3 subject to y(2)=2

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Q: dy 1. Determine the general solution of x = 2 – 4x3 dx

A: Since you have submitted two questions, we'll answer the first question. For the second question…

Q: 1. Find the general solution of 3 + = y*(2x*) dx

A: Since you have posted multiple questions in this question which are not interlinked so I have solved…

Q: Solve the initial value problem. dy + 5xy = 8x, y(0) = - 6 dx y =

A: topic - differential equations

Q: Solve: 3(1 + t?)(dy/dt) = 2ty(y³ - 1). %3D

A: Solve the integral 31+t2dydt=2tyy3-1. Use the separation of variable method. 1yy3-1y'…

Q: Solve using selaration of variables: xy^3 dx + ex^2 dy = 0.

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Q: Solve the initial value problem. dy 2xy = 8x, у(0) — 0 dx y =

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Q: Find the complete solution of √1 + x² dx + x(1 + y) = 0

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Q: Solve the equation (4y+2x– 5)dx + (6y +4x– 1)dy = 0 subject to the initial condition y(-1)= 2.

A: Consider a first order linear homogenous differential equation of the form, Pdx+Qdy=0→1 where P=fx,y…

Q: olve the initial value problem by standard method  (x^2+3y^2)dx-2xydy=0,  y(2)=6

A: We need to solve differential equationx2+3y2dx-2xydy=02xydy=x2+3y2dxdydx=x2+3y22xy

Q: (2х + Зу — 5)dx + (3x — у — 2)dy — 0

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Q: dx dy dx dy Use elimination to solve: + = e'; -= *+

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