Solve y' + 4y/x - x³ y? = 0 Find the general solution. Choose. What is the integrating factor? Choose. x^ -4 y = x^4 (C - In x) y^-1 = x^4 (C- In x) e^x^4 X^4 y^-1 = x ^ -4 (C - In x)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve y' + 4y/x - x³ y? = 0
Find the general solution.
Choose.
What is the integrating factor? Choose.
XA -4
y = x^4 (C - In x)
y^-1 = x^4 (C- In x)
e^x^4
x^4
yA-1 = x ^ -4 (C- In x)
Transcribed Image Text:Solve y' + 4y/x - x³ y? = 0 Find the general solution. Choose. What is the integrating factor? Choose. XA -4 y = x^4 (C - In x) y^-1 = x^4 (C- In x) e^x^4 x^4 yA-1 = x ^ -4 (C- In x)
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