Solve y (kx √√3) dx + (√3 − kx) dy O a. 2kx + 4√/31n|kx √3- O b. 2kx + 4√3ln|kx c. 2kx + 4√3 ln | kx - 2k In|y| √3 - 2k In ly √3+2k In y yz (kx + k sin (kz²) = C k sin (kz²) = C k sin (kz²) = C √3) cos (kz²) dz = 0

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