Solve 2sin2(x)−sin(x)−1=02sin2(x)-sin(x)-1=0 for all solutions. Your initial angle should be between 0 and 2π (not including 2π, and your initial angles should go from least to greatest. Consider 2nπ2nπ to have an initial angle of 0). Use n as your multiplier.

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
Problem 48PS
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Solve 2sin2(x)−sin(x)−1=02sin2(x)-sin(x)-1=0 for all solutions.

Your initial angle should be between 0 and 2π (not including 2π, and your initial angles should go from least to greatest. Consider 2nπ2nπ to have an initial angle of 0). Use n as your multiplier.

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