Some sequences hav converging subseguen.ces! Example xj=j" segue nces no en ceS ; 4?... } = { ,", 3'; {1,4,9,16, lim j j? l je IN}. %3D %3D This sey n We will laten that this prove nence has no conu. subseg . Part 1 HW4 imitate the proof below to prove any subsequence of the sequence above also diverges to infinity (not required)

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