Spot the erros in the following java code and correct to match the instructions: Print "userNum1 is negative." if userNum1 is less than 0. End with newline. Assign userNum2 with 4 if userNum2 is greater than 15. Otherwise, print "userNum2 is less than or equal to 15.". End with newline.
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Spot the erros in the following java code and correct to match the instructions:
Print "userNum1 is negative." if userNum1 is less than 0. End with newline.
Assign userNum2 with 4 if userNum2 is greater than 15. Otherwise, print "userNum2 is less than or equal to 15.". End with newline.
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- public class ReversedDigit { public static void main(String[] args) { Scanner scan = new Scanner(System.in); System.out.println("Please enter a number: "); int number = scan.nextInt(); int reversedNumber = 0; do { reversedNumber = number%10; number = number/10; } while (number > 0); }} Modify the coding example, to count what is the total of all digits of a number. For example, when user enters 301, your output is 4 because 3+0+1=4; when user enters 5116, your output is 13 (5+1+1+6 = 13).Here is the question: Write an application that accepts three Strings from the user and displays them in alphabetical order without regard to case. Here is the code so far just needs to be altered: import java.util.*; public class Alphabetize2 { public static void main(String[] args) { String str1, str2, str3; Scanner in = new Scanner(System.in); System.out.print("Enter first string >> "); str1 = in.nextLine(); System.out.print("Enter second string >> "); str2 = in.nextLine(); System.out.print("Enter third string >> "); str3 = in.nextLine(); // display strings in alphabetical order if(str1.toLowerCase().compareTo(str2.toLowerCase()) < 0 && str2.toLowerCase().compareTo(str3.toLowerCase()) < 0) System.out.println("You entered the strings in alphabetical order"); else System.out.println("You did not enter the words in alphabetical order"); } }Java Questions - (Has 2 Parts). Based on each code, which answer out of the choices "A, B, C, D, E" is correct. Each question has one correct answer. Thank you. Part 1 - Given the following code, the output is __. class Sample{ public static void main (String[] args){ try{ System.out.println(5/0);}catch(ArithmeticException e){ System.out.print("Divide by zero????");}finally{ System.out.println("5/0"); } }} A. Divide by zero????B. 5/0C. Divide by zero????5/0D. 5/0Divide by zero????E. "5/0" Part 2 - Given the following code, the output is __. try{ Integer number = new Integer("1"); System.out.println("An Integer instance.");}catch (Exception e){ System.out.println("An Exception.");} A. An Integer instance.B. An Exception.C. 1D. Error: ExceptionE. None of the options
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- When the given integer variable numberOfTools is: less than 14, output "Small tool box". between 14 inclusive and 39 inclusive, output "Mid-sized tool box". greater than 39, output "Need wall storage". End with a newline. Ex: If the input is 13, then the output is: (in java) Given Code: import java.util.Scanner; public class ToolDetails {public static void main(String[] args) {Scanner scnr = new Scanner(System.in);int numberOfTools; numberOfTools = scnr.nextInt();java Write a program that prompts the user to enter a point (x, y) and checks whether the point is within the rectangle centered at (0, 0) with width 10 and height 5. For example, (2, 2) is inside the rectangle and (6, 4) is outside the rectangle, as shown in the Figure. (Hint: A point is in the rectangle if its horizontal distance to (0, 0) is less than or equal to 10 / 2 and its vertical distance to (0, 0) is less than or equal to 5 / 2.) Here are sample runs of the program: Sample 1: Enter a point with two coordinates: 2 2 Point (2.0, 2.0) is in the rectangle Sample 2: Enter a point with two coordinates: 6 4 Point (6.0, 4.0) is not in the rectangle Analysis: (Describe the problem including input and output in your own words.) Design: (Describe the major steps for solving the problem.) Coding: (Go over your code step by step) Testing: (Describe how you test this program). In other words run your code with sample outputs.Q1) Write a method that checks whether two words are anagrams. Two words are anagrams if they contain the same letters in any order. For example, "silent" and "listen" are anagrams. Write a test program that prompts the user to enter two strings and, if they are anagrams, displays "anagram", otherwise displays "not anagram". Note: The header of the method is as follows: public static boolean isAnagram(String s1, String s2) Sample Input #1: Enter two strings: Silent listen Sample Output #1: The string “Silent” and “listen” are anagrams. Sample Input #1: Enter two strings: teach peach Sample Output #1: The string “teach” and “peach” aren’t anagrams.
- ntegers outerRange and innerRange are read from input. Complete the outer while loop so the inner loop executes (outerRange + 1) * innerRange times. Ex: If the input is 6 5, then the output is: Inner loop ran 35 times import java.util.Scanner; public class LoopCounter { public static void main (String[] args) { Scanner scnr = new Scanner(System.in); int outerRange; int innerRange; int count; int i; int j; outerRange = scnr.nextInt(); innerRange = scnr.nextInt(); count = 0; i = 0; while (/* Your code goes here */) { j = 0; while (j < innerRange) { ++count; ++j; } ++i; } System.out.println("Inner loop ran " + count + " times"); } }hasAnEvenDigit: Takes an int (n) as parameter and returns whether n has at least one digit whose value is even. Return true if the number has at least one even digit else false if none of the digits are even. For example, the call hasAnEvenDigit(33267) should return true and hasAnEvenDigit(7591) should return false. [Hint: n%10 returns the last digit and n/10 returns everything except the last digit] class Main {public static void main(String[] args) {}}Write an application that asks a user to type an even number or the sentinel value 999 to stop. When the user types an even number, display the message “Good job!” and then ask for another input. When the user types an odd number, display an error message, "x is not an even number", and then ask for another input. When the user types the sentinel value 999, end the program. import java.util.*; public class EvenEntryLoop { public static void main (String args[]) { // Write your code here } }