START: MOV CX, 0002 CLC

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
In execution of the following code with the
following bytes contents:
START:
CLC
MOV CX, 0002
MOV SI, 0300
MOV DI, 0302
LOOP:
ADC (SI), AL
INC SI
INC DI
DEC CX
JNZ LOOP
HLT
3CH, (0303H) = 4DH.
MOV AL, (DI)
(0300H) = 1AH, (0301H) = 2BH, (0302H) =
The result will be:
a. (0300H) = 1AH, (0301H) = 2BH, (0302H)
= 66H, (0303H) = 77H
b. (0300H) = 1AH, (0301H) = 2BH, (0302H)
= 3CH, (0303H) = 4DH
C. (0300H) = 1AH, (0301H) = 2BH, (0302H)
= 56H, (0303H) = 87H
d. None of the options given here.
Select one:
Transcribed Image Text:In execution of the following code with the following bytes contents: START: CLC MOV CX, 0002 MOV SI, 0300 MOV DI, 0302 LOOP: ADC (SI), AL INC SI INC DI DEC CX JNZ LOOP HLT 3CH, (0303H) = 4DH. MOV AL, (DI) (0300H) = 1AH, (0301H) = 2BH, (0302H) = The result will be: a. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 66H, (0303H) = 77H b. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 3CH, (0303H) = 4DH C. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 56H, (0303H) = 87H d. None of the options given here. Select one:
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