What would I specfically but in each box for step 2. Tutorial ExerciseUse the position function s(t) = -4.9t² + 750, which gives the height (In meters) of an object that has fallen for t seconds from a height of 750 meters. The velocity at time t = a seconds is given by the following.s(a)-s(t)a-tFind the velocity of the object when t = 2.limtingStep 1The velocity of the object when t = a= 2 2 Iss(2) - s(t)Ilmt-2- tStep 2Find s(2) by substituting 2 for t In s(t) = -4.9t² + 750.s(2) = -4.9(1² + 750cip (you cannot come back)

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Answered: Step 2 Find s(2) by substituting 2 for…

Step 2 Find s(2) by substituting 2 for t in s(t)= -4.9t2 + 750. s(2) = -4.9([ + 750 II Submit Skip (you cannot come back)

College Algebra

1st Edition

ISBN:9781938168383

Author:Jay Abramson

Publisher:Jay Abramson

Chapter3: Functions

Section3.2: Domain And Range

Problem 60SE: The height h of a projectile is a function of the time t it is in die air. The height in feet for t...

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Question

What would I specfically but in each box for step 2.

Tutorial Exercise
Use the position function s(t) = -4.9t² + 750, which gives the height (In meters) of an object that has fallen for t seconds from a height of 750 meters. The velocity at time t = a seconds is given by the following.
s(a)-s(t)
a-t
Find the velocity of the object when t = 2.
lim
ting
Step 1
The velocity of the object when t = a= 2 2 Is
s(2
) - s(t)
Ilm
t-2
- t
Step 2
Find s(2) by substituting 2 for t In s(t) = -4.9t² + 750.
s(2) = -4.9(
1² + 750
cip (you cannot come back)

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