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Step 3 Rewrite the integration in terms of u and v. 110 Step 4 (cos w)ew dw = (cos w)ew - Again integrate du = Je = 1 (cos w)ew + ew(sin w) dw by parts. -Jew(-sin(w) dw = (sin w)ew dw = (sin w)ew Let dv = ew dw, and integrate the differential equation to obtain the function v. V = = [ov = few dw = [ dv And let usin w. Differentiate u with respect to w. / (sin w)ew Submit Skip (you cannot come back) (sin(w) Substitute the expressions for u and v on the right side, and obtain the integral. -Je W ew sin (w)) dw dw sin (w) Dew dw ew dw

Step 3 Rewrite the integration in terms of u and v. 110 Step 4 (cos w)ew dw = (cos w)ew - Again integrate du = Je = 1 (cos w)ew + ew(sin w) dw by parts. -Jew(-sin(w) dw = (sin w)ew dw = (sin w)ew Let dv = ew dw, and integrate the differential equation to obtain the function v. V = = [ov = few dw = [ dv And let usin w. Differentiate u with respect to w. / (sin w)ew Submit Skip (you cannot come back) (sin(w) Substitute the expressions for u and v on the right side, and obtain the integral. -Je W ew sin (w)) dw dw sin (w) Dew dw ew dw

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I need help with step 4 of this problem I did step 1 2 and 3

help me fill in the blanks of step 4

Find or evaluate the integral using substitution first, then using integration by parts. S Step 1 To find the integral Let w = In x. Differentiate w in terms of x. 9- dx Thus, cos(In x) dx dw = dx Let dv Therefore, x = e. Differentiate x in terms of w. = S 1 X Jo cos(In x) dx, first use the substitution, then use the formula of integration by parts. W e cos(In x) dx = = SE Step 2 Apply the rule of integration by parts. Sudv 1 u dv = uv - V du -sin (w) e cos(w) dw v cos (w) ew dw and integrate the differential equation to obtain the function v. v = [ov = for ow = ²² dv W ew dw And let u = cos w. Differentiate u in terms of w. - sin (w) dw du lew 20 dw.
Transcribed Image Text:Find or evaluate the integral using substitution first, then using integration by parts. S Step 1 To find the integral Let w = In x. Differentiate w in terms of x. 9- dx Thus, cos(In x) dx dw = dx Let dv Therefore, x = e. Differentiate x in terms of w. = S 1 X Jo cos(In x) dx, first use the substitution, then use the formula of integration by parts. W e cos(In x) dx = = SE Step 2 Apply the rule of integration by parts. Sudv 1 u dv = uv - V du -sin (w) e cos(w) dw v cos (w) ew dw and integrate the differential equation to obtain the function v. v = [ov = for ow = ²² dv W ew dw And let u = cos w. Differentiate u in terms of w. - sin (w) dw du lew 20 dw.
Step 3 Rewrite the integration in terms of u and v. -Jew Step 4 I (cos w)ew dw = (cos w)ew. Again integrate Let dv = V = J du = = 1₁ ew(sin w) dw by parts. = [ov = [ew dv And let u = sin w. Differentiate u with respect to w. (cos w)ew + (sin(w) J ew dw, and integrate the differential equation to obtain the function v. ew dw dw = (sin w)ew dw = (sin w)ew ew(-sin (w) Substitute the expressions for u and v on the right side, and obtain the integral. - lew (sin w)ew Submit Skip (you cannot come back) I - sin (w) dw sin (w) ew dw Dew dw dw
Transcribed Image Text:Step 3 Rewrite the integration in terms of u and v. -Jew Step 4 I (cos w)ew dw = (cos w)ew. Again integrate Let dv = V = J du = = 1₁ ew(sin w) dw by parts. = [ov = [ew dv And let u = sin w. Differentiate u with respect to w. (cos w)ew + (sin(w) J ew dw, and integrate the differential equation to obtain the function v. ew dw dw = (sin w)ew dw = (sin w)ew ew(-sin (w) Substitute the expressions for u and v on the right side, and obtain the integral. - lew (sin w)ew Submit Skip (you cannot come back) I - sin (w) dw sin (w) ew dw Dew dw dw
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