Step 5 Notice that the original integral e70 sin(80) de is once again present. In fact, putting together all our work so far, if we let e70 sin(80) ·의가 cos(80) + 흑 +. I = e70 sin(80) de, we have I = + C1. This can be re-arranged to give us I = e70 sin(80) – 8/7 x 8/49 e70 cos(80) - 64/49 64/49 I + C1. %3D Step 6 We can move all the I terms to one side and get e70 sin(80) 8 re70 49 cos(80) + C1. I =

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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Step 5
Notice that the original integral
e70 sin(80) d0 is once again present. In fact, putting together all our work so far, if we let
e70 sin(80) d0, we have I =
·의가 cos(80) + 특 +
I =
70
+ C1.
This can be re-arranged to give us
I = e70 sin(80) -8/기 x
8/49 e70 cos(80) – 64/49
64/49 I + C1.
%3D
Step 6
We can move all the I terms to one side and get
8
-e70 cos(80) + C1.
49
I =
,70
Transcribed Image Text:Step 5 Notice that the original integral e70 sin(80) d0 is once again present. In fact, putting together all our work so far, if we let e70 sin(80) d0, we have I = ·의가 cos(80) + 특 + I = 70 + C1. This can be re-arranged to give us I = e70 sin(80) -8/기 x 8/49 e70 cos(80) – 64/49 64/49 I + C1. %3D Step 6 We can move all the I terms to one side and get 8 -e70 cos(80) + C1. 49 I = ,70
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