struct Simplestruct { int i; char c; double d; unsigned char a[11]; float f; }; struct Simplestruct * ssp; at int's are 4 bytes and have 4 byte alignment and that double ha and float has 4 byte alignment. rintf("ŝx\n",ssp) yields CA028, what is the address of eac should express the answers in hexadecimal.

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5. Memory Layout
Given the C struct definition below
struct Simplestruct {
int i;
char c;
double d;
unsigned char a[11];
float f;
};
struct Simplestruct
ssp;
Assume that int's are 4 bytes and have 4 byte alignment and that double has 8 byte
alignment and float has 4 byte alignment.
if calling printf("$x\n",ssp) yields CA028, what is the address of each
field? You should express the answers in hexadecimal.
&ssp->i =
&ssp->c =
&ssp->d =
&ssp->a =
&ssp->f =
Transcribed Image Text:5. Memory Layout Given the C struct definition below struct Simplestruct { int i; char c; double d; unsigned char a[11]; float f; }; struct Simplestruct ssp; Assume that int's are 4 bytes and have 4 byte alignment and that double has 8 byte alignment and float has 4 byte alignment. if calling printf("$x\n",ssp) yields CA028, what is the address of each field? You should express the answers in hexadecimal. &ssp->i = &ssp->c = &ssp->d = &ssp->a = &ssp->f =
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