Student Answer Appendix SA-8 17 75. 5 71.a 73. 30 259 Section 4.8 Solving Equations Containing Fractions Example 8 Solving an Equation by First Clearing Fractions 35 Skill Practice 3 Solve. Solve. x2 7 1 3 14 X 3 8 8 4 Solution: 4 4 3 is 14. 14 2 = 14 The LCD of -—х, -2, and 7 (2)- ( = 14 14 Multiply both sides by 14. 14 4 +14 (-2) = 14 3 Use the distributive property to 14 X multiply each term by 14. 14 Avoiding Mistakes 2 +14 (-2) 14 14 Be sure to multiply each term by 14. This includes the constant X Simplify each term. 14 term, -2 -8x 28 3 The fractions have been "cleared." -8x 28 +28 3 +28 Add 28 to both sides to isolate the x term. - 8x = 31 Apply the division property of equality to isolate x. -8x 31 2 1 -8 -8 31 The solution is -and checks in the original equation. 31 Answer = x 8. 26 8. Section 4.8 Practice Exercises e-Professors ALEKS Practice Problems Boost your GRADE at ALEKS.com! Videos Self-Tests Version 3.0 NetTutor Meicns mmended that you write an explanation for xnlanation iN MAT O022 Chapter 1: 1-21.8
Student Answer Appendix SA-8 17 75. 5 71.a 73. 30 259 Section 4.8 Solving Equations Containing Fractions Example 8 Solving an Equation by First Clearing Fractions 35 Skill Practice 3 Solve. Solve. x2 7 1 3 14 X 3 8 8 4 Solution: 4 4 3 is 14. 14 2 = 14 The LCD of -—х, -2, and 7 (2)- ( = 14 14 Multiply both sides by 14. 14 4 +14 (-2) = 14 3 Use the distributive property to 14 X multiply each term by 14. 14 Avoiding Mistakes 2 +14 (-2) 14 14 Be sure to multiply each term by 14. This includes the constant X Simplify each term. 14 term, -2 -8x 28 3 The fractions have been "cleared." -8x 28 +28 3 +28 Add 28 to both sides to isolate the x term. - 8x = 31 Apply the division property of equality to isolate x. -8x 31 2 1 -8 -8 31 The solution is -and checks in the original equation. 31 Answer = x 8. 26 8. Section 4.8 Practice Exercises e-Professors ALEKS Practice Problems Boost your GRADE at ALEKS.com! Videos Self-Tests Version 3.0 NetTutor Meicns mmended that you write an explanation for xnlanation iN MAT O022 Chapter 1: 1-21.8
Chapter9: Sequences, Probability And Counting Theory
Section: Chapter Questions
Problem 24RE: A ladder has 15 tapered rungs, the lengths of which increase by a common difference. The first rung...
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Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
Question
For this type of equation like this do I wanna fall of this solution as into looking for the least common denominator first distributing the least common denominator. And then simplifying before I multiply ?
Transcribed Image Text:Student Answer Appendix
SA-8
17
75.
5
71.a
73.
30
259
Section 4.8 Solving Equations Containing Fractions
Example 8
Solving an Equation by First Clearing Fractions
35
Skill Practice
3
Solve.
Solve.
x2
7
1
3
14
X 3
8
8
4
Solution:
4
4
3
is 14.
14
2 =
14
The LCD of
-—х, -2, and
7
(2)-
( =
14
14
Multiply both sides by 14.
14
4
+14 (-2) = 14
3
Use the distributive property to
14
X
multiply each term by 14.
14
Avoiding Mistakes
2
+14 (-2) 14
14
Be sure to multiply each term by
14. This includes the constant
X
Simplify each term.
14
term, -2
-8x
28 3
The fractions have been "cleared."
-8x
28 +28 3 +28
Add 28 to both sides to isolate
the x term.
- 8x = 31
Apply the division property of
equality to isolate x.
-8x
31
2
1
-8
-8
31
The solution is -and checks in
the original equation.
31
Answer
= x
8.
26
8.
Section 4.8 Practice Exercises
e-Professors
ALEKS
Practice Problems
Boost your GRADE at
ALEKS.com!
Videos
Self-Tests
Version 3.0
NetTutor
Meicns
mmended that you write an explanation for
xnlanation
iN
MAT O022
Chapter 1:
1-21.8
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