Substitute A = 2, B =-2 and C = 10 in equation (1), 20# 2 (-2)+10 2 2+4)-14 #2+42+5 2 2+4 14 #2+42+5 20# That is Integrate on both sides, 2c+ 4 (x - 1) (22 4x 5) 14 (« + 2)2 + 1 + 14 tan-1( 2) +C 02 +42+5 20x Thus, 024,40+5 Therefore, the value of the integral is 20x 024,40+5

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.9: Dividing Real Numbers
Problem 10MRE
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Why does 2x-10 become 2x-4-14??????

Substitute A = 2, B =-2 and C = 10 in equation (1),
20#
2 (-2)+10
2
2+4)-14
#2+42+5
2 2+4
14
#2+42+5
20#
That is
Integrate on both sides,
2c+ 4
(x - 1) (22 4x 5)
14
(« + 2)2 + 1
+ 14 tan-1( 2) +C
02 +42+5
20x
Thus,
024,40+5
Therefore, the value of the integral is
20x
024,40+5
Transcribed Image Text:Substitute A = 2, B =-2 and C = 10 in equation (1), 20# 2 (-2)+10 2 2+4)-14 #2+42+5 2 2+4 14 #2+42+5 20# That is Integrate on both sides, 2c+ 4 (x - 1) (22 4x 5) 14 (« + 2)2 + 1 + 14 tan-1( 2) +C 02 +42+5 20x Thus, 024,40+5 Therefore, the value of the integral is 20x 024,40+5
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