Substitution in the Indefinite Integral Part 1. Using the substitution: u = 10z² + 3z – 6. Re-write the indefinite integral then evaluate in terms of u- Note: answer should be in terms of u only Part 2. Back substituting in the antiderivative you found in Part 1. above we have (2z 10z+3z-6 Note: answer should be in terms of I only

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Substitution in the Indefinite Integral
Part 1.
Using the substitution: u =
10z? + 3x – 6. Re-write the indefinite integral then evaluate in terms of u.
(2x + )e10z²+3z-6 dæ
Note: answer should be in terms of u only
Part 2.
Back substituting in the antiderivative you found in Part 1. above we have
(2x + )e10z²+3z-6 dæ
Note: answer should be in terms of x only
Transcribed Image Text:Substitution in the Indefinite Integral Part 1. Using the substitution: u = 10z? + 3x – 6. Re-write the indefinite integral then evaluate in terms of u. (2x + )e10z²+3z-6 dæ Note: answer should be in terms of u only Part 2. Back substituting in the antiderivative you found in Part 1. above we have (2x + )e10z²+3z-6 dæ Note: answer should be in terms of x only
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