sum = 0; for (int i = 1; i< n; i = sum++ || 2*i)
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give a Θ(·) estimation of the running time as a function of n.
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give a Θ(·) estimation of the running time as a function of n.
- For function addOdd(n) write the missing recursive call. This function should return the sum of all postive odd numbers less than or equal to n. Examples: addOdd(1) -> 1addOdd(2) -> 1addOdd(3) -> 4addOdd(7) -> 16 public int addOdd(int n) { if (n <= 0) { return 0; } if (n % 2 != 0) { // Odd value return <<Missing a Recursive call>> } else { // Even value return addOdd(n - 1); }}Question#1: Let P and Q be integers and suppose F (P, Q) is recursively defined by: F(int P, int Q) if (P == 0) return Q else return F(P- 1, P + Q) Find and Trace F(8,1)Q // Write a program in C++ language that enters a number of integer numbers into a singular matrix whose size is renewed after asking the user about the number of numbers he wants to enter, then he collects these numbers and prints the result on the screen
- 1: |R|←|P| Reserve space for |P| = 13 values.2: x ← n3: for i ← 0 ...(|P| − 1) do4: c ← x div Pi Number of multiplicands Pi in x.5: Ri ← c6: x ← x − c · Pi7: end for8: return RA Java programmer could implement Algorithm by first modelling the primitivenumbers with the enumeration type RomanNumeral. Each enum constant (I, IV, ..., M) is declared with its decimal value, which can be accessed with the function getValue().Write a function that takes in an integer n and computes n!. Do this without recursion. In [ ]: deffactorial_iter(n):"""Takes in an integer n>0 and returns the product of all integers from 1 to n."""# YOUR CODE HEREraiseNotImplementedError() In [ ]: In [ ]: assert factorial_iter(6) == 720 assert factorial_iter(7) == 5040 assert factorial_iter(10) == 362880026 78.497 Bytes question. Write a recursive function that returns the sum of the digits of a given integer.Input format :Integer NOutput format :Sum of digits of NConstraints :0 <= N <= 10^9Sample Input 1 :12345Sample Output 1 :15Sample Input 2 :9Sample Output 2 :9 Solution:///////////// public class solution { public static int sumOfDigits(int input){ int sum; if(input<10){ return input; } sum = (input % 10) + sumOfDigits(input / 10); return sum; }}.
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- In C++ whats the answer from below ? int size = 10; for ( int i = -1; i < size ; i++) { arr[size - i] = i; } This array: has 12 positions is out of bounds has 10 positions has 11 positions•rewrite calculateSum function as a recursive function. m(i) = m(i-1) + i/(i+1), where i >=1In java: Develop a function that accepts an array of integers and returns their average. Develop a function that accepts an array of integers and a threshold value from the user. The function returns how many values in the array are strictly greater than the cutoff. Using the functions written for #1, #3, and #4, find the number of values above average in two randomly generated arrays. Develop two functions:a. a function that returns the index of the maximum value in an array of integers passed by a caller, the caller prints the returned index and the value at that indexb. a function that returns the index of the alphabetically first value in an array of strings, the caller prints the returned index and the value at that inde Develop two functions:a. a function that swaps the alphabetically first value in an array of Strings with the first value in the array. Call this function twice on two different arrays of Strings; in the caller, use the function written for #2b to display…