sum i=0 j = 12 varl = 3 var2 = 3 var3 = 0 for(i=0; i var3) { } } varl =varl - i; else { var3= var3+ i; } sum varl + var2+ var3; j = j-1 If you code it correctly, at the end sum contains 15 (decimal). Assume that variables are 32-bit signed integers variables You are not allowed to make any logical reduction to the code. You need to implement it the way it
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a masm x86 assembly
INCLUDE
.386
.model flat, stdcalll
.stack 4096
and
.code
and
main ENDP
END main
in the screen shot
PLEASE!!!!
Step by step
Solved in 4 steps with 2 images
- 1- Use bitwise operators to compute division and multiplication by a number that is power of 2. For example: bitwise_divide/multiply(num, 8/16/32/2/4/128) should use only bitwise operators to compute result.2- Write code that checks if a number is odd or even using bitwise operators.3- Write a program that checks if a number is positive/negative/zero.4- Write a function that returns toggle case of a string using the bitwise operators in placeInside the CPU mathematical opreations like addition, subtraction, multipication and division are done in bit level. To perform bit level operation in C programming, bitwise operations are used. Apply the knowledge you gained while learning the bitwise operators. Write a C program to input two integer from a user by using a single scanf. Compute and display the value for a&b, a\b, a*b. Write the algorithm also.Flip Bit to Win: You have an integer and you can flip exactly one bit from a O to a 1. Write code to find the length of the longest sequence of 1 s you could create.EXAMPLEInput: 1775Output: 8
- include <bits/stdc++.h> using namespace std; int MSD(int n){ if(n == 0) return 0; int k = log10(n); int x = pow(10,k); int ans = n/x; return ans; } int main() { int n; cin >> n; cout << MSD(n).Question: For every part that says "TODO" is a part you need to write. Correctly written code works if every "TODO" is written correctly. #include <stdio.h> void print_intbits(int num); int main(int argc, char *argv[]){int x; printf("x has only the 16th bit set\n");x = 1 << 16;print_intbits(x); printf("x as decimal: %d\n", x);printf("x as octal : %o\n", x);printf("x as hex : %x\n", x);printf("\n"); printf("set 19th bit as well\n");x = x | (1 << 19);print_intbits(x); printf("set 3rd bit as well\n");// TODO: set the indicate bit in x// ???print_intbits(x); printf("invert the bits\n");x = ~x;print_intbits(x); printf("clear the 8th bit\n");x = x & ~(1 << 8);print_intbits(x); printf("clear the 25th bit\n");// TODO: clear given bit in x// ???print_intbits(x); printf("clear all bits via xor\n");x = x ^ x;print_intbits(x); printf("place the pattern 110101 starting at bit 8\n");x = x | (0b110101 << 8);print_intbits(x); printf("place the pattern 10011111…#include <iostream>#include <cmath>#include <iomanip>using namespace std; int main() { double x; double y; double z; cin >> x; cin >> y; /* Your code goes here */ cout << fixed << setprecision(1); // setprecision(1) outputs z with 1 decimal place. cout << z << endl; return 0;} having trouble with this code in C++
- Python Programming- Computer-Assisted Instruction Part 1: Computer-Assisted Instruction (CAI) refers to the use of computers in education. Write a script to help an elementary school student learn multiplication. Create a function that randomly generates and returns a tuple of two positive one-digit integers. Use that function's result in your script to prompt the user with a question, such as: How much is 6 times 7? For a correct answer, display the message "Very good!" and ask another multiplication question. For an incorrect answer, display the message "No. Please try again." and let the student try the same question repeatedly until the student finally gets it right. Part 2: Varying the computer's responses can help hold the student's attention. Modify the program so that various comments are displayed for each answer. Possible responses to a correct answer should include 'Very good!' , 'Nice work!' and 'Keep up the good work!' Possible responses to an incorrect answer shojld…in python Write a function that receives a string containing a 32-bit hexadecimal integer. The function must return the string’s integer value. Write a function that receives an integer. The function must return a string containing the binary representation of the integer. Write a function that receives an integer. The function must return a string containing the hexadecimal representation of the integer. Write a function that adds two hexadecimal strings, each as long as 1,000 digits. Return a hexadecimal string that represents the sum of the inputs.c++ part2 and the rest plz 1- Given a set of numbers where all elements occur even number of timesexcept one number, find the odd occurring number” This problem can beefficiently solved by just doing XOR of all numbers.2- Use bitwise operators to compute division and multiplication by a numberthat is power of 2. For example: bitwise_divide/multiply(num,8/16/32/2/4/128) should use only bitwise operators to compute result.3- Write code that checks if a number is odd or even using bitwise operators.4- Write a program that checks if a number is positive/negative/zero.5- Write a function that returns toggle case of a string using the bitwiseoperators in place. this is the answer of the first exercice: #include <bits/stdc++.h> // include header file for standard header filesusing namespace std; int funintar[],intsizeintar[],intsizeintar[],intsize // start definition of function to check the odd occurences of the numbers{ int res = 0;…
- We are given an unsigned integer number represented by 16 bits. This number can be kept in a variable defined in C language as "uint16_t". Let's represent this variabe as "uint16_t x;" in our C code. a) keep the least significant 8 bits of this number in an unsigned character variable "x_low". b) Keep the most significant 8 bits of this number in an unsigned character variable "x_high". c) Form a new unsigned integer 16-bit variable in C language called "x_swap". This variable will keep the swapped version of the variable "x" such that the least significant 8 bits of the variable x will become the most significant 8 bits of the variable "x_swap". Also, the most significant 8 bits of the variable x will become the least significant 8 bits of the variable "x_swap".given ASCIIOFSET .FILL x0030 NegASCIIOFSET .FILL xFFD0 ASCIINewline .FILL x000d ; Newline ascii code ASCIISpace .FILL x0020 ; Space ascii code ASCIIComma .FILL x002C ; Comma ascii code Use LC-3 I/O device to print number, commas, and spaces in printCommaSpace subroutine, also check code to see if it follows instructions and modify accordingly/main.cpp:15:24 Implicit conversion loses integer precision: 'unsigned long' to 'int' #include<stdio.h>#include<string.h>int main(){ char thVl[20],thTmp; int q,thLngth; printf("Input: "); scanf("%s",thVl); thLngth=strlen(thVl)-1; for(q=0;q<strlen(thVl)/2;q++) { thTmp=thVl[q]; thVl[q]=thVl[thLngth]; thVl[thLngth--]=thTmp; } printf("\nReversed thVl: %s",thVl);}