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Summary of Derivatives of Transcen Let u be a differentiable function of z du (a)(e) =eu dr (b)(b) = b - Inb . d 1 du (c)(In u) == u dr d 1 du (d) -(log, u) de u lnb de du dr

Summary of Derivatives of Transcen Let u be a differentiable function of z du (a)(e) =eu dr (b)(b) = b - Inb . d 1 du (c)(In u) == u dr d 1 du (d) -(log, u) de u lnb de du dr

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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answer a, b, c, and d

Summary of Derivatives of Transcendental Functions Let u be a differentiable function of z. du d -(e") = eu dr (cos-¹(r)) dr da du d (b)(b) = br. Inb (tan-¹(z))= dr dr. d 1 du d (c) (In u) (cot-¹(2)) = dr u dr da d d 1 du (sec-¹(r))= (d) (log, u) dr da u lnb dr 1 du d d (csc-¹(x)) = (e) (sin-¹(x)) = dr VI-² de (F) (8) (h) (1) (j) 1 du √1 - dr F 1. du 1+z² dr 1 du 1+r² dr du 1 I√T²2²-1 dr 1 du I√1²¹-1 dr
Transcribed Image Text:Summary of Derivatives of Transcendental Functions Let u be a differentiable function of z. du d -(e") = eu dr (cos-¹(r)) dr da du d (b)(b) = br. Inb (tan-¹(z))= dr dr. d 1 du d (c) (In u) (cot-¹(2)) = dr u dr da d d 1 du (sec-¹(r))= (d) (log, u) dr da u lnb dr 1 du d d (csc-¹(x)) = (e) (sin-¹(x)) = dr VI-² de (F) (8) (h) (1) (j) 1 du √1 - dr F 1. du 1+z² dr 1 du 1+r² dr du 1 I√T²2²-1 dr 1 du I√1²¹-1 dr
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