Question
Asked Nov 19, 2019
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Suppose
2а, 1— 8а, 2 + 5а, -з
ат
and
55,
57,
=296
a4=
a5=
a6
Find a1, a2, and az.
= ID
а2
аз
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Suppose 2а, 1— 8а, 2 + 5а, -з ат and 55, 57, =296 a4= a5= a6 Find a1, a2, and az. = ID а2 аз

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Expert Answer

Step 1

From the given information,

If n %3D4, а, - 2а, - 8а, + 5а,
> -55%3 2а, - 8а, + 5а, ... (1)
If n %3D 5, a, — 2а, - 8а, + 5а,
3-57%3D2(-55)- 8a, + 5а, ... (2)
If n %3 6, а, 3D 2а, - 8а, +5а,
3 а, — 2а, + 8а, 3 5а,
296-2(-57) + 8(-55) +5а,
296+114-440 %3D 5а,
— -30%3D 5а,
=-6
m
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If n %3D4, а, - 2а, - 8а, + 5а, > -55%3 2а, - 8а, + 5а, ... (1) If n %3D 5, a, — 2а, - 8а, + 5а, 3-57%3D2(-55)- 8a, + 5а, ... (2) If n %3 6, а, 3D 2а, - 8а, +5а, 3 а, — 2а, + 8а, 3 5а, 296-2(-57) + 8(-55) +5а, 296+114-440 %3D 5а, — -30%3D 5а, =-6 m

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Step 2

Substitute a3 = –6 in ...

-57 2(-55)-8(-6) +5a
-57-2(-55)+ 8(-6)= 5a,
-57 110 48 5a
5=5a,
az=1
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-57 2(-55)-8(-6) +5a -57-2(-55)+ 8(-6)= 5a, -57 110 48 5a 5=5a, az=1

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Math

Calculus