Suppose a # b (mod m). Let r be the remainder of a when divided by <1> , and let s be the remainder of < 2 > _when divided by <3 > . Since the remainders are unequal, it follows that one must be bigger than the other: let us choose a to be the number with the larger remainder, so that r > <4> . By the definition of remainder, we may write a = p · m+ < 5> , and we may also write b = q. < 6> + <7> . Then by basic algebra, a– b = (p – q) ·<8 > + (r- <9> ). We want to show that r - s is the remainder of a – b when divided by m. To do this, we need to show that r - s is between 0 and < 10 > . Since r > s it follows that r – s > <11> . Furthermore, Since r 0, it follows that r-s< _ < 12 > . So we have shown that r - s is between < 13 > and<14> that r- s is the remainder of a – b when divided by m. However, r – s> 0, which means that a – b is not divisible by_ < 16 >. This is exactly what we needed to prove, so the proof is complete. , so by Proposition <15 > _ it follows
Suppose a # b (mod m). Let r be the remainder of a when divided by <1> , and let s be the remainder of < 2 > _when divided by <3 > . Since the remainders are unequal, it follows that one must be bigger than the other: let us choose a to be the number with the larger remainder, so that r > <4> . By the definition of remainder, we may write a = p · m+ < 5> , and we may also write b = q. < 6> + <7> . Then by basic algebra, a– b = (p – q) ·<8 > + (r- <9> ). We want to show that r - s is the remainder of a – b when divided by m. To do this, we need to show that r - s is between 0 and < 10 > . Since r > s it follows that r – s > <11> . Furthermore, Since r 0, it follows that r-s< _ < 12 > . So we have shown that r - s is between < 13 > and<14> that r- s is the remainder of a – b when divided by m. However, r – s> 0, which means that a – b is not divisible by_ < 16 >. This is exactly what we needed to prove, so the proof is complete. , so by Proposition <15 > _ it follows
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.4: Mathematical Induction
Problem 8E
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