Suppose f(x) = √. Give the function for each of the following transformations. The graph of f(x) reflected across the x-axis. Of(x) = -√ Of(x) = Of(x) = -x -√√√x The graph of f(x) shifted right 5 units Of(x)=√x - 5 Of(x)=√x + 5 Of(x) = √√x + 5 Of(x)=√x - 5 The graph of f(x) shifted down 1 units Of(x)=√x+1 Of(x)=√x - 1 Of(x)=√x-1 Of(x)=√x+1 The graph of f(x) shifted left 5 units and shifted up 1 units. Of(x) = √√√x + 5+1 Of(x)=√x+5-1 Of(x)=√x-5-1 Of(x) = √√x - 5+1 The graph of f(x) stretched vertically by a factor of 5. Of(x) = √5x 1 Of(x) = 5 ○ f(x) = -√√√x Of(x) = 5√x

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
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Chapter9: Quadratic Functions And Equations
Section9.2: Transformations Of Quadratic Functions
Problem 49PFA
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Suppose f(x) = √. Give the function for each of the following transformations.
The graph of f(x) reflected across the x-axis.
Of(x) = -√√x
Of(x) =
Of(x) = -x
-√√√x
The graph of f(x) shifted right 5 units
Of(x)=√x
- 5
Of(x)=√x
+ 5
Of(x) = √√x + 5
Of(x)=√x - 5
The graph of f(x) shifted down 1 units
Of(x)=√x+1
Of(x)=√x - 1
Of(x)=√x-1
Of(x)=√x+1
The graph of f(x) shifted left 5 units and shifted up 1 units.
Of(x) = √√√x + 5+1
Of(x)=√x+5-1
Of(x)=√x-5-1
Of(x) = √√√x - 5+1
The graph of f(x) stretched vertically by a factor of 5.
Of(x) = √5x
1
Of(x) =
5
○ f(x) = -√√√x
Of(x) = 5√√√x
Transcribed Image Text:Suppose f(x) = √. Give the function for each of the following transformations. The graph of f(x) reflected across the x-axis. Of(x) = -√√x Of(x) = Of(x) = -x -√√√x The graph of f(x) shifted right 5 units Of(x)=√x - 5 Of(x)=√x + 5 Of(x) = √√x + 5 Of(x)=√x - 5 The graph of f(x) shifted down 1 units Of(x)=√x+1 Of(x)=√x - 1 Of(x)=√x-1 Of(x)=√x+1 The graph of f(x) shifted left 5 units and shifted up 1 units. Of(x) = √√√x + 5+1 Of(x)=√x+5-1 Of(x)=√x-5-1 Of(x) = √√√x - 5+1 The graph of f(x) stretched vertically by a factor of 5. Of(x) = √5x 1 Of(x) = 5 ○ f(x) = -√√√x Of(x) = 5√√√x
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