Suppose T: P2→M22 is a linear transformation whose action on a basis for P2 is as follows: 0 3 T(x+1) = 9. -6 2 0 4 T(-2x2 ) = T(x2+2x+1)= 2 -2 12 -8 Describe the action of T on a general polynomial, using a, b, and c as constants. 3a-b -a+2b T(ax2+bx+c) = -a+8b a-7b The correct answer is: За-3ь+3с -а+2b+с T(ax2 +bx+c)= ах -a+4b+5c _a¬3b-3c

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.5: The Kernel And Range Of A Linear Transformation
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Hi, I have included two image. One with red color on top is the previous question and the sample of the answer. The second image  is the question 

Suppose T: M2.2 P2 is a linear transformation whose action on a basis for M2.2 is as follows:
0 0
-6x2-4 T
2 0
0 -1
x²-x-1
-3 -3
11
6х2-3х+3 т
2 2
—2х2-2х-2 Т
-3 -3
0 0
Describe the action of T on a general matrix, using x as the variable for the polynomial and a, b, c, and d as constants. Use the 'A' character to indicate an exponent, e.g. ax^2-bx+c.
a b
T
c d
Transcribed Image Text:Suppose T: M2.2 P2 is a linear transformation whose action on a basis for M2.2 is as follows: 0 0 -6x2-4 T 2 0 0 -1 x²-x-1 -3 -3 11 6х2-3х+3 т 2 2 —2х2-2х-2 Т -3 -3 0 0 Describe the action of T on a general matrix, using x as the variable for the polynomial and a, b, c, and d as constants. Use the 'A' character to indicate an exponent, e.g. ax^2-bx+c. a b T c d
Suppose T: P2→M22 is a linear transformation whose action on a basis for P2 is as follows:
0 3
T(x+1) =
6 2
4
T(-2x² ) =
T(x2+2x+1)=
2 -2
9 -6
12 -8
Describe the action of T on a general polynomial, using a, b, and c as constants.
3a-b -a+2b
T(ax2+bx+c)=
-a+8b a-7b
The correct answer is:
За-3b+3с —а+26+с
T(ax2+bx+c)=
-a+4b+5c a-3b-3c
Transcribed Image Text:Suppose T: P2→M22 is a linear transformation whose action on a basis for P2 is as follows: 0 3 T(x+1) = 6 2 4 T(-2x² ) = T(x2+2x+1)= 2 -2 9 -6 12 -8 Describe the action of T on a general polynomial, using a, b, and c as constants. 3a-b -a+2b T(ax2+bx+c)= -a+8b a-7b The correct answer is: За-3b+3с —а+26+с T(ax2+bx+c)= -a+4b+5c a-3b-3c
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