Suppose that the input is 0 0 8 12 50 7 13 -1. What is the output of the following C++ code?

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Suppose that the input is 0 0 8 12 50 7 13 -1. What is the output of the following C++ code?

int num, sum, count;
cin >> sum;
cin >> count;
cin >> num;
while (count <= 4)
{
sum = sum + num;
count++;
cin >> num;
}
cout << "Sum = " << sum << endl,
Transcribed Image Text:int num, sum, count; cin >> sum; cin >> count; cin >> num; while (count <= 4) { sum = sum + num; count++; cin >> num; } cout << "Sum = " << sum << endl,
Expert Solution
Step 1

Befor while loop,

Variable sum will take 1st input so, sum = 0.

Variable count will take 2nd input so, count = 0.

Variable num will take 3rd input so, num = 8.

 

inside while loop :

1st iteration :       sum = 0 + 8 = 8 ,     count  = 1,    num = 4th input ( 12 ) .

2nd iteration :      sum = 8 + 12 = 20 ,     count  = 2,    num = 5th input ( 50 ) .

3rd iteration :       sum = 20 + 50 = 70 ,     count  = 3,    num = 6th input ( 7 ) .

4th iteration :       sum = 70 + 7 = 77 ,     count  = 4,    num = 7th input ( 13 ) .

5th iteration :       sum = 77 + 13 = 90 ,     count  = 5,    num = 8th input ( -1 ) .

 

Now, as, count becomes 5 which is greater than 4. so, loop will break.

 

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