Suppose that two random variables Y1 and Y2 are independent, that is, for all values of y, and y2, P((Yı = y1) N (Y2 = y2)) = P(Y1 = y1)P(Y2 = y2) that is, the events (Yı = y1) and (Y2 = y2) are independent. Suppose also that Y1 and Y2 have the same Geometric distribution, that is Y ~ Geometric(p) and Ý, ~ Geometric(p). Define a third random variable Y as the sum of Y1 and Y2, that is, Y = Y1 +Y2.

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section9.3: Binomial Probability
Problem 2E: If a binomial experiment has probability p success, then the probability of failure is...
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Suppose that two random variables Y1 and Y2 are independent, that is, for all values of y1 and y2,
P((Yı = y1) n (Y2 = y2)) = P(Y1 = y1)P(Y2 = 42)
that is, the events (Y1 = y1) and (Y2 = y2) are independent. Suppose also that Y1 and Y2 have the
same Geometric distribution, that is Y1 - Geometric(p) and Ý, - Geometric(p). Define a third
random variable Y as the sum of Y and Y2, that is, Y = Y1 +Y2.
Transcribed Image Text:Suppose that two random variables Y1 and Y2 are independent, that is, for all values of y1 and y2, P((Yı = y1) n (Y2 = y2)) = P(Y1 = y1)P(Y2 = 42) that is, the events (Y1 = y1) and (Y2 = y2) are independent. Suppose also that Y1 and Y2 have the same Geometric distribution, that is Y1 - Geometric(p) and Ý, - Geometric(p). Define a third random variable Y as the sum of Y and Y2, that is, Y = Y1 +Y2.
By considering the Theorem of Total Probability and the partitioning result
y-1
(Y = y) = U ((Yı = t) n (Y2 = y – t))
t=1
for y = 2,3, ..., derive the pmf of Y.
Transcribed Image Text:By considering the Theorem of Total Probability and the partitioning result y-1 (Y = y) = U ((Yı = t) n (Y2 = y – t)) t=1 for y = 2,3, ..., derive the pmf of Y.
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