Suppose that unicorns have one gene that codes for color, where S is silver and s is white. The unicorns also have another gene that codes for tail color, where P is purple and p is pink.If these two genes are unlinked, what is the probability that a cross between Ss Pp × Ss pp parents will produce two out of eight offspring that are white with pink tail?

Question
Asked Feb 13, 2019

Suppose that unicorns have one gene that codes for color, where S is silver and s is white. The unicorns also have another gene that codes for tail color, where P is purple and p is pink.

If these two genes are unlinked, what is the probability that a cross between Ss Pp × Ss pp parents will produce two out of eight offspring that are white with pink tail?

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Expert Answer

Step 1

When two genes are involved, the cross between them is termed as a dihybrid cross. The genes can be linked or unlinked. 

Linked genes are those which are present very near to each other, on the same chromosome. These genes are called linked because they remain together at the time of gamete formation. 

Unlinked genes are those which are either present far from each other (more than a distance of 50 map units) or are on the different chromosome. These genes are called unlinked because they assort independently of each other at the time of gamete formation.

Step 2

The genes for body color are not linked to gene for tail color. So, they will assort independently of each other.

Given, 

Parental Genotype                  SsPp                                                                    Sspp

Phenotype                              silver body, purple tail                             Silver body, pink tail

Possible gametes from one parent (SsPp) are SP, Sp, sP, sp

Possible gametes from second parent (Sspp) are  Sp, sp

Step 3

On mating between parents, the possible phenotypes and genotypes are:

The probability of each phenotype is:

  • Silver body, purple tail = 3/...
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