Suppose {u1,u2,...,un} is a set of vectors that span V, and that {v1,v2,...,vk} is an independent set of vectors in V. Explain why v1=x1u1+x2u2+...+xnun must have a nontrivial solution. Explain why we may assume x1≠0. (Hint: x1 is the first unknown because u1 was the first vector in our spanning set.) Explain why this means u1 is in the span of {v1,u2,...,un} Explain why this means {v1,u2,...,un} also spans V.
Suppose {u1,u2,...,un} is a set of vectors that span V, and that {v1,v2,...,vk} is an independent set of vectors in V. Explain why v1=x1u1+x2u2+...+xnun must have a nontrivial solution. Explain why we may assume x1≠0. (Hint: x1 is the first unknown because u1 was the first vector in our spanning set.) Explain why this means u1 is in the span of {v1,u2,...,un} Explain why this means {v1,u2,...,un} also spans V.
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.3: Spanning Sets And Linear Independence
Problem 47EQ
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Suppose {u1,u2,...,un} is a set of
Explain why
v1=x1u1+x2u2+...+xnun
must have a nontrivial solution.
Explain why we may assume x1≠0. (Hint: x1 is the first unknown because u1 was the first vector in our spanning set.)
Explain why this means u1 is in the span of {v1,u2,...,un}
Explain why this means {v1,u2,...,un} also spans V.
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