equation of plane through point that contains a line Suppose we need to find an equation of the plane that passes through (1, 2, -2) that contains the line:x = 2t, y = 3-t, z = 1 + 3t.A normal vector to the required plane is:[a] (input a number from below)(1) <-6, -9, 1) (2) (2, – 1, 3) (3) (1, 2, - 2X4) The answer is not given.

Answered: Image /qna-images/answer/342844a4-eaa8-49a5-9366-221c8307d8e0.jpg

Suppose we need to find an equation of the plane that passes through (1, 2, -2) that contains the lin x = 2t, y = 3-t, z = 1 + 3t. A normal vector to the required plane is:[a] (input a number from below) @<-6, -9, 1> (2 (2, - 1, 3) (3 (1, 2, -2)4) The answer is not given.

Suppose we need to find an equation of the plane that passes through (1, 2, -2) that contains the lin x = 2t, y = 3-t, z = 1 + 3t. A normal vector to the required plane is:[a] (input a number from below) @<-6, -9, 1> (2 (2, - 1, 3) (3 (1, 2, -2)4) The answer is not given.

Algebra and Trigonometry (MindTap Course List)

4th Edition

ISBN:9781305071742

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter9: Vectors In Two And Three Dimensions

Section9.6: Equations Of Lines And Planes

Problem 2E

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Question

equation of plane through point that contains a line

Suppose we need to find an equation of the plane that passes through (1, 2, -2) that contains the line:
x = 2t, y = 3-t, z = 1 + 3t.
A normal vector to the required plane is:[a] (input a number from below)
(1) <-6, -9, 1) (2) (2, – 1, 3) (3) (1, 2, - 2X4) The answer is not given.

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