Suppose we need to find an equation of the plane that passes through (1, 2, -2) that contains the line:X = 2t, y = 3-t, z = 1 + 3t. A normal vector to the required plane is: 2 (input a number from below) O<-6, - 9, 1) (2 (2, – 1, 3) (3 <1, 2, – 2)(4) The answer is not given. The equation of the required plane is ax + by + cz = d, where (a, b, c, d) = (input a number from below) (1 (6, 9, – 1, 26) (2 (2, – 1, 3, 0) (3 (-6, - 9, 1, -24) (4 The answer is not given.

Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Vectors In Two And Three Dimensions
Section9.6: Equations Of Lines And Planes
Problem 2E
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find normal vector/equation of a plane containing a point and parallel to a line containing that point

Suppose we need to find an equation of the plane that passes through (1, 2, -2) that contains the line:X = 2t, y = 3-t, z = 1 + 3t.
A normal vector to the required plane is: 2
(input a number from below)
(1 <-6, -9, 1> (2 (2, – 1, 3) (3 <1, 2, – 2>4) The answer is not given.
The equation of the required plane is ax + by + cz = d, where (a, b, c, d)
(input a number from below)
(1 (6, 9, – 1, 26) (2) (2, - 1, 3, 0) (3 (-6, - 9, 1, -24) (4 The answer is not given.
Transcribed Image Text:Suppose we need to find an equation of the plane that passes through (1, 2, -2) that contains the line:X = 2t, y = 3-t, z = 1 + 3t. A normal vector to the required plane is: 2 (input a number from below) (1 <-6, -9, 1> (2 (2, – 1, 3) (3 <1, 2, – 2>4) The answer is not given. The equation of the required plane is ax + by + cz = d, where (a, b, c, d) (input a number from below) (1 (6, 9, – 1, 26) (2) (2, - 1, 3, 0) (3 (-6, - 9, 1, -24) (4 The answer is not given.
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