Suppose· X · has probability-density-function (p.d.f) fx(x) = 7(1+x²)³ ° which one is the p.d.f.. for Y=2X. A 2 fr(y)= π(4+ y²) B f(y)=- 1 π(1+4y²) fx(y)= 1 л(1+y²) 1 fr(y) == arctan y π C D

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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3. (单选题 3.0分)
1
Suppose X has probability density function (p.d.f) f (x)=.
π(1+x²)'
for Y=2X.+
A
2
fx(y) =
x(4+ y²)
B
fy(y)=-
1
π(1+4y²)
fr(y) =
1
π(1+ y²)
1
fr(y) == arctan y
π
C
D
which one is the p.d.f..
Transcribed Image Text:3. (单选题 3.0分) 1 Suppose X has probability density function (p.d.f) f (x)=. π(1+x²)' for Y=2X.+ A 2 fx(y) = x(4+ y²) B fy(y)=- 1 π(1+4y²) fr(y) = 1 π(1+ y²) 1 fr(y) == arctan y π C D which one is the p.d.f..
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