Suppose X1,.., X50 for k = 1,2, 3, 4 are independent 2- dimensional random samples from 4 treatments. Suppose the Between (B) and Within (W) sum of squares and cross product matrices are as follows 1911 1372 В 250 50 W 1372 3773 50 250 Test the hypothesis that Ho : u, = µ, = H = H, at level a = .05, %3D where u, , k = 1, 2, 3, 4 are the population mean vector of treatments %3D k = 1, 2, 3, 4, respectively. %3D Note that |W| = 5327819, |B| = 60000, |B+ W| = 6671619 %3D %3D x3(.05) = 5.99, x(.05) = 12.59 Since -(196) * log. (.7986) > x:(.05) we reject Hoat level a = .05. (196) log. (0.009) > x² (.05) we reject Hoat level a = .05. (196)* log. (.7986) > x(.05) we reject Hoat level a = .05. Since - (196) log, (0.009) > x3(.05) we reject Hoat level a = .05.

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A1
Suppose X1..., X50, for k = 1, 2, 3, 4 are independent 2-
dimensional random samples from 4 treatments. Suppose the Between
(B) and Within (W) sum of squares and cross product matrices are as
follows
1911
1372
250
50
W
B
1372 3773
50
250
Test the hypothesis that Ho : u, = µ, = H, = H, at level a = .05,
where u, , k = 1, 2, 3, 4 are the population mean vector of treatments
k = 1, 2, 3, 4, respectively.
%3D
Note that W = 5327819, |B|
= 60000, |B+ W| = 6671619
%3D
%3D
X3(.05) = 5.99, xG(.05) = 12.59
Since -(196) * log. (.7986) > x(.05) we reject Hoat level a = .05.
O Since -(196) log. (0.009) > x(.05) we reject Hoat level a = .05.
O Since -(196) * log, (.7986) > x(.05) we reject Hoat level a = .05.
O Since - (196) log, (0.009) > X(.05) we reject Hoat level a = .05.
Transcribed Image Text:Suppose X1..., X50, for k = 1, 2, 3, 4 are independent 2- dimensional random samples from 4 treatments. Suppose the Between (B) and Within (W) sum of squares and cross product matrices are as follows 1911 1372 250 50 W B 1372 3773 50 250 Test the hypothesis that Ho : u, = µ, = H, = H, at level a = .05, where u, , k = 1, 2, 3, 4 are the population mean vector of treatments k = 1, 2, 3, 4, respectively. %3D Note that W = 5327819, |B| = 60000, |B+ W| = 6671619 %3D %3D X3(.05) = 5.99, xG(.05) = 12.59 Since -(196) * log. (.7986) > x(.05) we reject Hoat level a = .05. O Since -(196) log. (0.009) > x(.05) we reject Hoat level a = .05. O Since -(196) * log, (.7986) > x(.05) we reject Hoat level a = .05. O Since - (196) log, (0.009) > X(.05) we reject Hoat level a = .05.
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