Suppose X1,.., X50 for k = 1,2, 3, 4 are independent 2- dimensional random samples from 4 treatments. Suppose the Between (B) and Within (W) sum of squares and cross product matrices are as follows 1911 1372 В 250 50 W 1372 3773 50 250 Test the hypothesis that Ho : u, = µ, = H = H, at level a = .05, %3D where u, , k = 1, 2, 3, 4 are the population mean vector of treatments %3D k = 1, 2, 3, 4, respectively. %3D Note that |W| = 5327819, |B| = 60000, |B+ W| = 6671619 %3D %3D x3(.05) = 5.99, x(.05) = 12.59 Since -(196) * log. (.7986) > x:(.05) we reject Hoat level a = .05. (196) log. (0.009) > x² (.05) we reject Hoat level a = .05. (196)* log. (.7986) > x(.05) we reject Hoat level a = .05. Since - (196) log, (0.009) > x3(.05) we reject Hoat level a = .05.
Suppose X1,.., X50 for k = 1,2, 3, 4 are independent 2- dimensional random samples from 4 treatments. Suppose the Between (B) and Within (W) sum of squares and cross product matrices are as follows 1911 1372 В 250 50 W 1372 3773 50 250 Test the hypothesis that Ho : u, = µ, = H = H, at level a = .05, %3D where u, , k = 1, 2, 3, 4 are the population mean vector of treatments %3D k = 1, 2, 3, 4, respectively. %3D Note that |W| = 5327819, |B| = 60000, |B+ W| = 6671619 %3D %3D x3(.05) = 5.99, x(.05) = 12.59 Since -(196) * log. (.7986) > x:(.05) we reject Hoat level a = .05. (196) log. (0.009) > x² (.05) we reject Hoat level a = .05. (196)* log. (.7986) > x(.05) we reject Hoat level a = .05. Since - (196) log, (0.009) > x3(.05) we reject Hoat level a = .05.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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