Suppose you have a matrix x = I 2 3 4 5 -20 6 . Which of the following will evaluate to 1 * ? 23 4 5
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- Dont the matrix V,P dont need any value?I do not understand this expression. so is c[i][j] += a[i][h] * b[h][j] mean c[i][j] = a[i][h] * b[h][j] + c[i][j]?? ; We do not know about the + matrix c right?I am having trouble with a individual coding problem I am doing in python: Ar = int(input("How many rows does your matrix have? "))Ac = int(input("How many columns does your matrix have? ")) win = GraphWin('Matrix A', 300,300) win.setBackground('white') for p in range(Ac):y = 75 + 40*pfor q in range(Ac):x = 50 + 50*qinputText = Entry(Point(x,y), 3)inputText.setText('0')inputText.draw(win) ## The issue I having is that I want to be able to get the users inputs from their entries so that I can do matrix operations on them. However, anytime I try to append their entries at best I just get their last entry repeated (n)(m) times. I would be very thankful if you can show me how I can change my code so that I append all user entries correctly.
- Which of the following is a false statement if arbitrary matrices A, B, and C for which the indicated sums and products are defined? Note: A^T = Transpose of A a.) AB + AC = A(B + C) b.) If A is an n x n matrix, then (A^2)^T = (A^T)^2 c.) A^T + B^T = (A + B)^T d.) (ABC)^T = (C^T)(A^T)(B^T)Given a matrix of m x n elements (m rows, n columns),return all elements of the matrix in spiral order.For example,Given the following matrix:[ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ]]You should return [1,2,3,6,9,8,7,4,5].""" def spiral_traversal(matrix): res = [] if len(matrix) == 0: return res row_begin = 0 row_end = len(matrix) - 1 col_begin = 0 col_end = len(matrix[0]) - 1 while row_begin <= row_end and col_begin <= col_end: for i in range(col_begin, col_end+1): res.append(matrix[row_begin][i]) row_begin += 1 for i in range(row_begin, row_end+1): res.append(matrix[i][col_end]) col_end -= 1 if row_begin <= row_end: for i in range(col_end, col_begin-1, -1): res.append(matrix[row_end][i]) row_end -= 1 if col_begin <= col_end: for i in range(row_end, row_begin-1, -1): res.append(matrix[i][col_begin]) col_begin += 1write a C++ program to Given a matrix of dimension m*n where each cell in the matrix can have values 0, 1 or 2 whichhas the following meaning:0: Empty cell1: Cells have fresh oranges2: Cells have rotten orangesSo we have to determine what is the minimum time required so that all the oranges becomerotten. A rotten orange at index [i,j] can rot other fresh orange at indexes [i-1,j], [i+1,j], [i,j-1],[i,j+1] (up, down, left and right). If it is impossible to rot every orange then simply return -1.Examples:Input: arr[][C] = { {2, 1, 0, 2, 1},{1, 0, 1, 2, 1},{1, 0, 0, 2, 1}};Output:All oranges can become rotten in 2 time frames.Input: arr[][C] = { {2, 1, 0, 2, 1},Tahir Iqbal Department of Computer Sciences. BULC{0, 0, 1, 2, 1},{1, 0, 0, 2, 1}};Output:All oranges cannot be rotten.Below is algorithm.1) Create an empty Q.2) Find all rotten oranges and enqueue them to Q. Also enqueuea delimiter to indicate beginning of next time frame.3) While Q is not empty do following3.a) While delimiter in…
- Let y be a column vector: y = [1, 2, 3, 4, 5, 6] so that y.shape = (6,1). Reshape the vector into a matrix z using the numpy.array.reshape and (numpy.array.transpose if necessary) to form a new matrix z whose first column is [1, 2, 3], and whose second column is [4, 5, 6]. Print out the resulting array z.When you have a matrix below, how do you print this as a matrix? Example) mat = 1 2 3 2 3 4 When you do the following for-loop, what do you get? Cumulative addition of each element in either row or column direction.okl ook sk ook ok o st s ook skl ok sk s ki sl ok sk ok sk s ok ks ok sk ok ook ok 01 (A) Create the following matrix K K= K = 0.25 0.5 0:75 1:0 125 15 1:75 2 4 6 8 10 12 14 25 30 35 40 45 50 55 And answer the following: (a) Create a matrix Ga such that its first row includes the elements of the second column of K followed by the elements of the fifth column of K, the second row of Ga include the first six elements of the second row of K, and the third row of Ga includes the last six elements of the third row of K. (b) Create a matrix Gb in which the first two rows and columns 3 through 6 of K.
- Can someone help me with the following C++ problem please? An array "matrix" with N lines and M columns and I have to rotate the middle square 90 degrees to the left. The lines and the columns of the matrix has to start form 1. Restrictions 1 ≤ n, m ≤ 50 1 ≤ mt[i][j] ≤ 3 000 1 ≤ i ≤ n, 1 ≤ j ≤ m 1 ≤ i + l - 1 ≤ n 1 ≤ j + l - 1 ≤ m EX: Input 4 41 2 3 45 6 7 89 10 11 1213 14 15 162 2 2 Output: 1 2 3 45 7 11 89 6 10 1213 14 15 16Construct a square matrix with NN rows and NN columns consisting of nonnegative integers from 00 to 10^{18}1018, such that its determinant is equal to 11, and there are exactly A_iAi odd numbers in the ii-th row for each ii from 11 to NN, or report there isn't such a matrix. Standard input The first line contains a single integer NN. Each of the next NN lines contains a single integer A_iAi. Standard output If there is no solution, output \text{-}1-1. Otherwise, print NN lines, each consisting of NN integers, representing the values of the constructed matrix. If there are multiple solutions, print any. Constraints and notes 2 \le N \le 502≤N≤50 1 \leq A_i \leq N1≤Ai≤N For 40\%40% of the test files, N \le 17N≤17.Consider the following snapshot of a system: Allocation Max Available A B C D A B C D A B C D P0 0 0 1 2 0 0 1 2 1 5 2 0 P1 1 0 0 0 1 7 5 0 P2 1 3 5 4 2 3 5 6 P3 0 6 3 2 0 6 5 2 P4 0 0 1 4 0 6 5 6 Answer the following questions using the banker’s algorithm: a). What is the content of the matrix Need? b). Is the system in a safe state? c). If a request from process P1 arrives for (0,4,2,0), can the request be granted immediately?