Suppose you repeatedly flip a fair coin. Use the normal approximation discussed above to (approximately)compute the probability that it takes more than 210 flips to get 100 heads (you should use the continuitycorrection).The coin is unfair with probability of observing a head being 1/3. Suppose you repeatedly flip this unfaircoin. Use the normal approximation discussed above to (approximately) compute the probability that ittakes more than 210 flips to get 60 heads (you should again use the continuity correction).

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Asked Dec 9, 2019
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Suppose you repeatedly flip a fair coin. Use the normal approximation discussed above to (approximately)
compute the probability that it takes more than 210 flips to get 100 heads (you should use the continuity
correction).
The coin is unfair with probability of observing a head being 1/3. Suppose you repeatedly flip this unfair
coin. Use the normal approximation discussed above to (approximately) compute the probability that it
takes more than 210 flips to get 60 heads (you should again use the continuity correction).
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Suppose you repeatedly flip a fair coin. Use the normal approximation discussed above to (approximately) compute the probability that it takes more than 210 flips to get 100 heads (you should use the continuity correction). The coin is unfair with probability of observing a head being 1/3. Suppose you repeatedly flip this unfair coin. Use the normal approximation discussed above to (approximately) compute the probability that it takes more than 210 flips to get 60 heads (you should again use the continuity correction).

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Expert Answer

Step 1

The probability that it takes more than 210 flips to get 100 heads is obtained below:

The required formula is,

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х, - P(X = x) = Trx(1- P) <(1- p)

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Step 2

From the given information, flip a fair coin getting head or tail that is equally ...

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X, -* P(X =x) = rx(1- p) P(X,>210)= P(X, > 210.5) 100 210.5- 0.5 = P z> 100×(0.5) 0.5 10.5 =1-P Z< 14.1421 =1-P(Z <0.742) [:: From standardnormal table] =1-0.7704 = 0.2296

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