Take the Laplace transform of the following initial value and solve for Y(s) = L{y(t)}: [sin(nt), 10, Y(s) Next take the inverse transform of Y(s) to get y(t) Use step(t-c) for uc(t) Note: = y" + 9y = π π 1 1 (6²+7²) (8² +9) = 7²-9 (5²+9=2+²) 0≤t<1 1≤t y(0) = 0, y'(0) = 0

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