tan 0 If u= sec 0, then de= sec 0

Q: tan 0 + tan? 0 = sec* 0 - sec² 0

A: This question is taken from trigonometry in which we have to prove the given identity  We can write…

Q: sin 20 + cos 20 = cot x tan x

A: Prove this using a right angled triangle and the pythagorean identity.

Q: sin( cos" + un ") 12 + tan

A: first we convert all trigonometric identities in to one trig identity. like as cos inverse and tan…

Q: Verify the identity: sec2 t/tan t = sec t csc t

A:

Q: 12 tan(0) = find sec(0) 12

A: sec(theta)=? cos(theta) = ?

Q: tan 0 If u = sec 0, then de= sec 0 I u/ūdu NZ du (B Vu C) Vudu

A:

Q: secθ-tanθsinθ=1/secθ

A:

Q: True or False secθ=1/sinθ

A: We have to say that the given statement is true or false: sec θ=1sin θ We know the identity, cos θ…

Q: tan (x) = sec (x)

A: We know that  tan(x) = sin(x)/cos(x)  Sec(x) = 1/cos(x)  So ,  sin(x)/cos(x) = 1/cos(x)

Q: Sin = 0.23 find tan, cot, sec, and csc

A: Given sin x=0.23Since csc x=1sin x         csc x=10.23=4.35

Q: sin: tan cos : cot: cos csc O csc / sec 1/tan cos / sin

A: Solution:

Q: tan e = 4 and 0 terminates in QIII 3 sin 0 Cos e = Csc e sec e cot 0

A:

Q: tan(x+1) Find y' of y =

A: y=tanx+1x

Q: sin Icos 15° csc 35° tan 4 sec 3 cot 85" : tan 5" : sec55" : CoS 3 :: Csc :: sin 75" cot ::

A:

Q: \tan ^{2} \theta-\tan \theta=0

A: To solve the equation: tan2θ-tanθ=0 Solution: Factorizing the given equation.…

Q: tan e sec³ e de ' O sec '0 de

A: Consider the given integral as ∫tan3θsec3θdθ

Q: establish each identity.

A: To prove: tanθ+secθ-1tanθ-secθ+1=tanθ+secθ

Q: sin 0 Simplify: I + cos 0 O sec 0 – tan 0 O cse 0 + tan ở O csc 0 + cot 0 О csc @ — сot @

A: Given expression is  sinθ/(1 + cosθ)

Q: Prove the identity. tan 0( tan 0 + cot 0) = sec ²e

A: The given identity,      tanθtanθ+cotθ=sec2θ

Q: tan x 4. Simplify the expression tan x+cot x O sin æ sin x O cos? a COS COs x

A:

Q: /tan x sin x cos x

A: given = ∫tan (x)sin (x) .cos(x)dx

Q: Establish each identity.

A: Given identity is  sin4θ+sin2θcos4θ+cos2θ=tan3θ

Q: (cos) + tan ) d0 (sec® + tan@sec²0) do cos?0 A True B) False

A: Topic = Integration TRUE

Q: tan x+tan y 1. Simplify: cotx+coty

A:

Q: establish each identity.

A: We have to prove the given identity: sec θcosec θ+sin θcos θ=2 tan θ We know the relation between…

Q: tan : sin z :: cot : cos r cos/ sin O 1/tan O cos csc csc / sec

A:

Q: Degree: Sign of LC: as x→-0, y→ as x 00, y→

A: y=6-2x-4x2+5x3y=5x3-4x2-2x+6Standard form: 5x3-4x2-2x+6

Q: . sec 0 = sin 0(tan 0 + cot 0)

A: Given expression: sinθtanθ+cotθ=secθ We know that  tanθ=sinθcosθ and cotθ=cosθsinθ

Q: (sec 0 + csc 0)(cos 0 – sin 0)

A:

Q: Tan(x)=1.find x if x lies in 1st quadrant

A:

Q: sec(x)sin(x)−2sin(x)=0

A: Explanation of the solution is given below...

Q: tan 0 csc 0 cos 0 = 1

A: Given,           tanθcscθcosθ=1

Q: • sin 0 r cos 0 dr do.

A:

Q: sec 0 = cos 0 = sin 0 = tan 0/2 = sin 20 = sin 0/2 =

A: Follow the procedure given below.

Q: sin (cot−1 (5/2 ))

A:

Q: tan(=2 ») =x+y. 5. tan Determine y'.

A:

Q: cot x sec x sin x = 1

A:

Q: Establish each identity.

A: To prove:sec4θ - sec2θ = tan4θ + tan2θ

Q: Finu sin(a) and cos(ß), tan(a) and cot(B), and sec(a) and csc(ß). 20 35 (a) sin(a) and cos(B) (b)…

A:

Q: sin 40 + sin 20 12. cos 48 + cos 20 A- tan 30 B B tan 0 cot 30 D D cot 0

A:

Q: Part 3 Establish the identity. sec 0 CSc 0 %3D sec 0-1

A:

Q: (cos0+ tan@) do sec® + tan@sec²0) de cos20 A) True B) False

A:

Q: tan (90° - x) = 9.3. What is cot (x)? %3D

A: Some trigonometric identities: sin(90-θ)=cos θ cos(90-θ)=sin θ

Q: tan theta +cot theta )^(2) = sec^2 theta csc^2 theta

A: Proving the equation

Q: csce+sece 5-6. Prove that tane + cot0 sine+cose

A:

Q: 10 [cot 0 · sec 0 · sin 0] =

A:

Q: tan x 4. Simplify the expression tan x+cot x sin x O cos? æ cos x sin? x

A:

Q: tan X If y = (Sin x)

A: y=sinxtanx Applying natural logarithm on both sides, we get ⇒lny=lnsinxtanx⇒lny=tanx lnsinx

Q: tan '6 (secx)"dx tan

A: