- tan(-0) | • Show that = sin 0. For each step in sec 0 your process, explain what identity you are using to take that step, using the vocabulary in Week 6 Video 2 to describe the identities. • Solve the equation cot2 0 – 3 csc 0 = 2 for all - solutions 0, showing all steps in your process. Use set notation and k E Z to index your solutions. Leave your answers in exact form (for example, square roots and inverse trigonometric functions), but you may include decimal approximations if it helps you verify your solutions graphically using technology. • Solve the equation sin 0 + 3 cos 0 = 1 for 0Е [О, 2л).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.3: Trigonometric Functions Of Real Numbers
Problem 26E
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tan(-0)
• Show that
= sin 0. For each step in
sec 0
your process, explain what identity you are using
to take that step, using the vocabulary in Week
6 Video 2 to describe the identities.
• Solve the equation cot? 0 – 3 csc 0 = 2 for all
solutions 0, showing all steps in your process.
Use set notation and k E Z to index your
solutions. Leave your answers in exact form (for
example, square roots and inverse trigonometric
functions), but you may include decimal
approximations if it helps you verify your
solutions graphically using technology.
• Solve the equation sin 0 + 3 cos 0 = 1 for
0€ [0, 2л).
Transcribed Image Text:tan(-0) • Show that = sin 0. For each step in sec 0 your process, explain what identity you are using to take that step, using the vocabulary in Week 6 Video 2 to describe the identities. • Solve the equation cot? 0 – 3 csc 0 = 2 for all solutions 0, showing all steps in your process. Use set notation and k E Z to index your solutions. Leave your answers in exact form (for example, square roots and inverse trigonometric functions), but you may include decimal approximations if it helps you verify your solutions graphically using technology. • Solve the equation sin 0 + 3 cos 0 = 1 for 0€ [0, 2л).
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