tan (58°) 1.40 m (1.4 m)(tan58°) = x (1.4 m)(tan58°) %3D х%3D (1.4)(1.6) II

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 4E
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1.40m
142m
1.40m
Transcribed Image Text:1.40m 142m 1.40m
tangent 0
opposite
adjacent
tan (58°)
1.40 m
(1.4 m)(tan58°) = x
%3D
x = (1.4 m)(tan58°)
(1.4)(1.6)
X =
x - 2.24047 m
х %3D 2.24 m
Again for H we use :
cosine e =
base
hypotenuse
cos (58°)
1.40m
H
1.40m
cos (58°)
H
= 2.64191 m
%3D
Transcribed Image Text:tangent 0 opposite adjacent tan (58°) 1.40 m (1.4 m)(tan58°) = x %3D x = (1.4 m)(tan58°) (1.4)(1.6) X = x - 2.24047 m х %3D 2.24 m Again for H we use : cosine e = base hypotenuse cos (58°) 1.40m H 1.40m cos (58°) H = 2.64191 m %3D
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