Ten signals, each requiring 4000 Hz, are multiplexed onto a single channel using FDM. What is the minimum bandwidth required for the multiplexed channel? Assume that the guard bands are 400 Hz wide.

Q: A channel has a bit rate of 4 kbps and a propagation delay of 20 msec For what range of frame sizes…

A: The Answer is in Below Steps

Q: Ten signals, each requiring 4000 Hz, are multiplexed onto a single channel using FDM. What is the…

A: The answer is

Q: A channel has a bit rate of 4 kbps and a propaga- tion delay of 20 msec. For what range of frame…

A: The Answer is

Q: Suppose, BanglaLink has 4 voice channels, each of 60Mbps. They use synchronous TDM to multiplex…

A: Answer:

Q: Ten signals, each requiring 3000 hz, are multiplexed onto a single channel using FDM. How much…

A: Here in this question question we have given Ten signals, each requiring 3000 hz.we are using FDM…

Q: If there ware no noise, how many signal levels would be needed to achieve the channel capacity of 8…

A: Here is the explanation

Q: 2. (a) Suppose a radio channel occupies a bandwidth of 11 kHz. We need to multiplex 14 radio…

A: Here, I have to provide a solution for the above question.

Q: nt from one

A: TDM-Time-division multiplexing (TDM) is a method for communicating and getting independent signals…

Q: Five Channels each with a 100 KHz bandwidth are to be multiplexed together using Frequncy division…

A: Answer is.  The minimum bandwidth is 540 Khz.

Q: Assume that a voice channel occupies a bandwidth of 8 kHz. We need to multiplex 10 voice channels…

A: Given: Channel bandwidth = 8kHz Guard bands = 1000Hz = 1kHz Number of channels = 10   to find:…

Q: Ten signals, each requiring 4000 Hz, are multiplexed onto a single channel using FDM. What is the…

A: The answer is

Q: Six channels, each with a 200 kHz bandwidth are to be multiplexed using FDM together. What is the…

A: It is an analog technique that can be applied when the bandwidth of a link (in hertz) is greater…

Q: . What is the theoretical capacity of a channel for the following case?             Bandwidth = 1…

A: What is the theoretical capacity of a channel for the following case? Bandwidth =1MHz     SNRdB=20

Q: what is the throughput if the system produces the 1000 frames/sec then A pure ALOHA network…

A: throughput of ALOHA network is calculated in step 2.

Q: Assume that a voice channel occupies a bandwidth of 4 kHz. We need to multiplex 10 voice channels…

A: In go-back-n protocol, given the size of the sequence number field is 8. then the sequence number is…

Q: (Compute the maximum channel utilization for a MAN which uses CSMA mechanism and has a length of 50…

A: Introduction :Given , A MAN , uses CSMA mechanism Length = 50 Km Bandwidth = 50 Mbps Frame size =…

Q: a) A pure ALOHA channel is going to be shared among some number of stations. Each station is…

A: Actually, 1 byte =8 bits. given each station is transmitting a 1024 -byte frame average every 28…

Q: Is it true that a narrowband channel transfers data at a snail's pace? Why?

A: Introduction: Narrowband communication uses a narrow bandwidth. A narrowband channel is one in which…

Q: Assume having a low-pass noiseless channel that spans from a Frequency of 0Hz to 130Hz, to send at a…

A: please upvote for my efforts thanks!   answer:   bit rate= 2* bandwidth * log2(number of levels)

Q: re 8 input signals each requiring a bandwidth of 3 MHz, what is the minimum bandwidth required for…

A: Given 2. In FDM, if there are 8 input signals each requiring a bandwidth of 3 MHz, what is the…

Q: Consider sender 1 is sending data bit -1 with CDMA code (1, 1, 1, -1, 1, -1, -1, -1) and sender 2 is…

A: The CDMA code sent by the Sender1 is (1, 1, 1, -1, 1, -1, -1, -1) and The CDMA code sent by the…

Q: what is the throughput if the system produces the 500 frames/sec then A pure ALOHA network transmits…

A: The Answer is

Q: The minimal frame size in a CSMA/CD network with a data throughput of 10 Mbps is discovered to be…

A: Question :- The minimal frame size in a CSMA/CD network with a data throughput of 10 Mbps is…

Q: (i) Consider a transmitter employing sliding window protocol for flow control with a window size set…

A: Propogation delay =Tt= 500ms   Transmission delay = Tp = 200*8/20*10^3 = 80 ms For sliding window…

Q: III. The figure below shows synchronous TDM, the data rate for each input connection is 1 Mbps. If 1…

A:

Q: Q1) How does FDM divide the shared channel over different users at the same time?

A: Given: Details around process of FDM divide the shared channel over different users at the same…

Q: A pure ALOHA network transmits 200-bit frames on a shared channel of 200 kbps. What is the…

A: Actually, Network is consists of two or more computers that are linked in order to share resources…

Q: (Dont copy) Four digital channels each transmitting at rate 2 Mbps with 4 bits are carried by one…

A: FDM is an analog multiplexing technique FDM is an analog multiplexing techniquethat combines analog…

Q: A corporation has a medium with a 7 MHz bandwidth (lowpass). The corporation needs to create 9…

A: he baud is defined as the number of changes in the signal level with in a second. The bandwidth of…

Q: For simplicity, let's assume that a voice channel has an 8-kilohertz bandwidth. It is necessary to…

A: As it is said in the question: Channel bandwidth=8KHz  Guard bands=1000Hz=1KHz  Number of channels…

Q: Four channels are multiplexed using TDM. If each channel sends 100 bytes /s and we multiplex 5 bits…

A: i. The multiplexer is shown in the figure.  Show the frame (at least three) traveling on the link…

Q: Five channels, each with a 100 kHz bandwidth, are to be multiplexed together What is the minimum…

A: Five channels, each with a 100 kHz bandwidth, are to be multiplexed together What is the minimum…

Q: Assume having a narrow low-pass channel that spans from a Frequency of 0Hz to 5400HZ, and a digital…

A: Here we calculate the minimum frequency required for analog by using the given information and fill…

Q: Multiplexing occurs at the physical layer via TDM, FDM, and CDM. What are the advantages and…

A: Multiplexing's Benefits: - A single medium may carry more than one signal. - A medium's bandwidth…

Q: What is the number of signal levels required to achieve a data rate of 12400 bps using a channel…

A: Data rate = 12400 bps Bandwidth = 3100 Hz Levels = ?

Q: Consider sliding window protocol for 80Mbps point - to - point link with propagation delay of 2 sec.…

A: Given, Bandwidth = 80 Mbps Frame Size = 4 KB = 4096 * 8 bits = 32768 bits Propagation delay = tp = 2…

Q: III. The figure below shows synchronous TDM, the data rate for each input connection is 1 Mbps. If 1…

A:

Q: 40 devices share a clean ALOHA channel. The drawer is 2μs in size. Because they want the devices to…

A: Here given is the number of channels as 40. So our N will be 40. Drawer is 2 micro seconds. So our…

Q: Assume having a low-pass noiseless channel that spans from a Frequency of OHz to 180HZ, to send at a…

A: please do upvote for my efforts ! answer: bit rate = 2* bandwidth * log2(number of levels)

Q: Given a transmission rate of 1 Gbps and a propagation speed of  200m / μ sec , how many meters of…

A: Transmission Rate = 1 Gbps = 109 bits per second Propagation Speed = 200 metre / micro second = 200…

Q: Suppose, you have 11 channels, each of 55 MBps. You have to use synchronous TDM to multiplex these…

A: The solution for the above given question is given below:

Q: A group of N stations share a 56-kbps pure ALOHA channel. Each station outputs a 1000-bit frame on…

A: Introduction

Q: Compute the maximum channel utilization for a MAN which uses CSMA mechanism and has a length of 50…

A: Introduction :Given , MAN network is given here which uses CSMA mechanism,length = 50 kmbandwidth =…

Q: Consider a communication channel with bandwidth B = 8000 Hz. Suppose the channel has a…

A:

Q: Five channels, each with a 400-KHz bandwidth, are to be multiplexed together. What is the minimum…

A: In a communication channel, the transmission media have multiple channels in which a single channel…

Q: what is the throughput if the system produces the 500 frames/sec then A slooted ALOHA network…

A: The slotted Aloha calculation is

Transmission media

A communication channel that transmits data from a source to a recipient is referred to as "transmission media." Electromagnetic impulses are used to transmit data. Transmission media's primary purpose is to transmit data in the form of bits via a local area network (LAN). In data transport, it is the physical link that connects the transmitter and receiver. Transmission medium is part of layer 1 or physical layer of the ISO/OSI (Open System Interconnection) model.