ter 13 Factoring Polynomials53. 2z6 8z5 - 42z4+24ab383. 4h2-23h- 6= 055. 10 + бр? + 19p85. 2584. q - 144 = 057. 9w2 - 6wz + z210086. 5v2 - v 087. x(x - 6) = -8P-57, which trinomials are perfect89. 9s212s = -488. 367260t =-25als?91. 2(p2 - 66) - 13p90. 3(y2 4) 20y193. x-4x = 0.92. 2y3-18y2= -28ywote the formula to factor eachSection 13.7a + b294. The base of a parallelogram is 1 ft longer thantwice the height. If the area is 78 ft', what are thebase and height of the parallelogram?completely62. d-6495. A ball is tossed into the air from ground levelwith initial speed of 16 ft/sec. The height of theball is given by the equation64. 4-25k2where h is theh = -162 + 16t (t 0)66. y2 +121ball's height in

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Asked Nov 20, 2019
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How do I answer 84 

ter 13 Factoring Polynomials
53. 2z6 8z5 - 42z4
+24ab3
83. 4h2-23h
- 6
= 0
55. 10 + бр? + 19p
85. 25
84. q - 144 = 0
57. 9w2 - 6wz + z
2
100
86. 5v2 - v 0
87. x(x - 6) = -8
P-57, which trinomials are perfect
89. 9s212s = -4
88. 367260t =-25
als?
91. 2(p2 - 66) - 13p
90. 3(y2 4) 20y
1
93. x-4x = 0
.92. 2y3-18y2= -28y
wote the formula to factor each
Section 13.7
a + b2
94. The base of a parallelogram is 1 ft longer than
twice the height. If the area is 78 ft', what are the
base and height of the parallelogram?
completely
62. d-64
95. A ball is tossed into the air from ground level
with initial speed of 16 ft/sec. The height of the
ball is given by the equation
64. 4-25k2
where h is the
h = -162 + 16t (t 0)
66. y2 +121
ball's height in
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ter 13 Factoring Polynomials 53. 2z6 8z5 - 42z4 +24ab3 83. 4h2-23h - 6 = 0 55. 10 + бр? + 19p 85. 25 84. q - 144 = 0 57. 9w2 - 6wz + z 2 100 86. 5v2 - v 0 87. x(x - 6) = -8 P-57, which trinomials are perfect 89. 9s212s = -4 88. 367260t =-25 als? 91. 2(p2 - 66) - 13p 90. 3(y2 4) 20y 1 93. x-4x = 0 .92. 2y3-18y2= -28y wote the formula to factor each Section 13.7 a + b2 94. The base of a parallelogram is 1 ft longer than twice the height. If the area is 78 ft', what are the base and height of the parallelogram? completely 62. d-64 95. A ball is tossed into the air from ground level with initial speed of 16 ft/sec. The height of the ball is given by the equation 64. 4-25k2 where h is the h = -162 + 16t (t 0) 66. y2 +121 ball's height in

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Expert Answer

Step 1

Given:

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2-144 0

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Step 2

Solution of the given quadratic...

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q-144=0 q=144 q=t144 q=t12

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