Test the series for convergence or divergence using the Alternating Series Test. 8(-1)"e-n n = 1 Identify b Test the series for convergence or divergence using the Alternating Series Test. lim b n-co Since lim bn 0 and b S b for all n, the series converges Watch It n = 0 Need Help? Read it n+ 1
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- Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the convergence or divergence of the series using other methods. (If you need to use or –, enter INFINITY or –INFINITY, respectively.) ∑ upper bound= infinity n^5/4^n lower bound = n=1 limit as n approaches infinity of |an +1 /(an)|Determine the convergence or divergence of the series using any appropriate test from this chapter. Identify the test used. ∑n=0 [7n+1 / 8n]Determine whether the series converges or diverges. The answer is diverges, and I do get the same answer when I do limit comparison test with bn = 1/6n. But I was wondering can't we do this with test for divergence? That's what I did the first time and got = 0, therefore convergent, but it wrong. Why is that I can't use test for divergence??
- Test the series for convergence or divergence using the alternating series test. 16) Σ n=1 to infinity (ncos(nπ))/(2^n)state whether the series converges or diverges and by which convergence test. Options: a. diverges-alternating series test b. converges ratio test c. converges alternating series test d. diverges integral comparison test e. diverges ratio test f. diverges alternating series test ∞∑n=1 1 n10 ---------- 6 + n11 ∞∑n=1 4n ------ n10 ∞∑n=1 n2·4n ------- n!state whether the series converges or diverges and by which convergence test. Options: a. diverges-alternating series test b. converges ratio test c. converges alternating series test d. diverges integral comparison test e. diverges ratio test f. diverges alternating series test ∞∑n=1 (−1)n n --------- 5 n + 6 ∞∑n=1 5 n2 ---------- 1 + n8 ∞∑n=1 (−1)n n3 ----------- 5 + n4
- Study the power series: - Using Limit Comparison Test show that this series converges when x = −2. - Justify if the series is absolutely convergent, conditionally convergent, or divergent at x = 12? - Determine the radius and interval of convergence of the power series.Select the FIRST correct reason why the given series diverges . A. Diverges because the terms don't have limit zero (nth Term Test for Divergence)B. Divergent geometric seriesC. Divergent p seriesD. Integral testE. Comparison with a divergent p seriesF. Cannot apply any test done so far in classTest the series for convergence or divergence and state the name of the test and criteria. [summation symbol from n =1 to infinity] (-1)n 1/(n+n1/2)