A normed space X is said to be strictly convex if for x # y in X with |||| = 1 = ||yl|, we have ||x+y|| < 2. This says that the mid-point (x + y)/2 of two distinct points a and y on the unit sphere of X does not lie on the unit sphere of X, but it lies in the open unit ball U(0, 1) of X. In particular, no line segment lies on the unit sphere. Request explain marked portion

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter6: More On Rings
Section6.2: Ring Homomorphisms
Problem 6E
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A normed space X is said to be strictly convex if for xy in
X with |||| = 1 = ||y||, we have ||x+y|| < 2.
This says that the mid-point (x+y)/2 of two distinct points r
and y on the unit sphere of X does not lie on the unit sphere of X,
but it lies in the open unit ball U(0, 1) of X. In particular, no line
segment lies on the unit sphere.
Request explain marked portion
Transcribed Image Text:A normed space X is said to be strictly convex if for xy in X with |||| = 1 = ||y||, we have ||x+y|| < 2. This says that the mid-point (x+y)/2 of two distinct points r and y on the unit sphere of X does not lie on the unit sphere of X, but it lies in the open unit ball U(0, 1) of X. In particular, no line segment lies on the unit sphere. Request explain marked portion
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Thank you understood theoretically, but unable to visualize. Can you please draw a rough diagram to explain

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