The 498-N force is applied to the 89-kg block, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the block. The force is positive if to the right, negative if to the left. H₂ = 0.66 H₂ = 0.52 36° P = 498 N

icon
Related questions
Question
The 498-N force is applied to the 89-kg block, which is stationary before the force is applied. Determine the magnitude and direction
of the friction force F exerted by the horizontal surface on the block. The force is positive if to the right, negative if to the left.
H₂ = 0.66
H = 0.52
Answer: F= i
36°
N
P = 498 N
Transcribed Image Text:The 498-N force is applied to the 89-kg block, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the block. The force is positive if to the right, negative if to the left. H₂ = 0.66 H = 0.52 Answer: F= i 36° N P = 498 N
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer