The 8255 shown in Figure below is configured as follows: port A as input, B as output, and all the bits of port C as output. (a) Find the port addresses assigned to A, B, C, and the control register, basic address is (00H). (b) Find the control byte (word) for this configuration. DO D7 DO D7 A. IOW IOR WR RD A0 A0 CL A2- A1 A1 CS CU A7 个介介
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- Identify the addressing modes used for the source and destination operands, and thencompute the physical address for the specified operand in each of the following instructions:(Assume all missing data.)1. MOV CX, [DI] (Source operand)2. MOV [BP]+BETA, AX (Destination operand)3. XCHG BX, [FF02] (Source operand)liomework: Identify the addressing modes used for the source and destination operands, and then compute the physical address for the specified orx•rand in each of the following instructions: a) Mov +XYZ,AH (Destination operand) b) Mov tBX) (Destination operand) Suppose that BX=030016, 010016.Identify the addressing modes used for the source and destination operands, and then compute the physical address for the specified operand in each of the following instructions: a) MOV [DI]+XYZ,AH (Destination operand)b) MOV [BX][DI]+XYZ,AL (Destination operand)c) MOV DI,[SI] (Source operand)d) MOV CL,XYZ[BX+SI] (Source operand)e) MOV DX, [BP] (Source operand)f) MOV AL, XYZ[BP+DI] (Source operand)g) MOV AL, [BP+SI-20016] (Source operand)
- Computer Science Please answer this question in assembly language with .asm extension. The code given in 99Heater.asm file is: ; ===== Heater and Thermostst on Port 03 ==========================; ===== 99Heater.asm ==============================================; ===== Heater and Thermostst on Port 03 ========================== MOV AL,0 ; Code to turn the heater off OUT 03 ; Send code to the heater IN 03 ; Input from Port 03 AND AL,1 ; Mask off left seven bits JZ Cold ; If the result is zero, turn the heater on HALT ; Quit Cold: MOV AL,80 ; Code to turn the heater on OUT 03 ; Send code to the heater END; ================================================================= Fix the program 99Heater.asm so that the temperature will stay at 21 ºC. Please solve the question in assembly language. I will definitely give you THUMBS UP.What addresses in the output portion of the datapath are mapped to the DSR and DDR respectively? a. )DSR: xFE02, DDR, xFE00 b.) DSR: xFE06, DDR, xFE04 c.) DSR: x300, DDR, x306 d.) DSR: xFE00, DDR, xFE02 e.) DSR: xFE04, DDR, xFE06When a byte of data is write to the memory address A4673H, the state of the control signal which occur in this cycle are. a. BHE# = 0, A0 = 1, M/IO# = 0, DT/R# = 1, RD# = 1, WR# = 0, DEN# = 0 b.BHE# = 1, A0 = 0, M/IO# = 0, DT/R# = 1, RD# = 0, WR# = 1, DEN# = 1 c. BHE# = 1, A0 = 0, M/IO# = 0, DT/R# = 1, RD# = 0, WR# = 1, DEN# = 0 d. BHE# = 0, A0 = 1, M/IO# = 1, DT/R# = 1, RD# = 1, WR# = 0, DEN# = 0
- In a Mil-Std 1553 Bus, one of the Remote Terminals (Terminal Address 4)would like to send the altitude of the aircraft, 1000ft (16-bit unsigned integer)from one of its subsystems, radio altimeter (subaddress 2) to a display subsystem(subaddress 7) at another Remote Terminal (Terminal Address 9). a. Please explain the information transfer on the bus. b. Please provide binary representation for one of the messages.A) Identify the addressing modes used for the source and destination operands and determine the physical address accessed by each of the following instructions (Assume all missing data.) (Choose Two Only): 1. MOV CX, [DI] (Source operand) 2. MOV [BP]+BETA, AX (Destination operand) 3. XCHG BX, [FF02] (Source operand)1) Jump and Jump and Link instructions have a six-bit op-code and a 26-bit jump address field. How is the full 32-bit Jump Address calculated? The jump address field is sign-extended six bits to the left. The leftmost four bits of the PC are concatenated with the jump address field, and two bits of zero are concatenated to the end of that. The leftmost six bits of the PC are concatenated with the jump address field. The jump address is ANDed with Register 0 to produce the jump address. -------------------------------------------------------------------------------- 2) How is a branch target address calculated? Sign-extend bits 15:0 of the instruction, append two bits of zeros, and add the result to the PC. Zero extend bits 15:0 of the instruction, append two bits of ones, and subtract the result from the PC. Add the immediate operand to register zero, and sign extend the result. Concatenate the leftmost 16 bits of the PC with the rightmost 16 bits of the instruction.…
- Draw the diagrams of given addressing modes. Show it with examples also. 1- Indexed Addressing a. Postindex b. PreindexQ2. The 8-bit registers AR, BR, CR, and DR initially have the following values: AR= 11010010, BR= 11100011, CR= 10111001 , DR= 10101011 Determine the 8-bit values in each register after the execution of the following sequence of microoperations. AR <-AR + BR CR <- CR ^ DR, BR <- CR + 1 AR <-AR – CRAs part of MC68000, the names of the addressing modes that are not permitted for destination are defined, along with the reasons why.