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The algorithm shown below is * suitable for 1- Start 2- Read the value of N,A 3-1=0:k=3 4- I=l+1 5- F=1; j=0 6-j=j+1 7-F=F*j 8- If j < I then goto step 6 9-S=S+(-1)^(21)*K*A*F 10- k=k+1 11- IfI < N then goto step 4 12- End S=4A+5A(2!)+ 6A(3!)+.Nterms S=4A-5A(2!)+6A(3!)-.N terms The equation is. O the equation is O S=3A+4A(2!)+ 5A(3!)+..Nterms S=-3A+4A(2!)-5A(3!)+.N terms The equation is O the equation is C S=3A-4A(2!)+5A(3!)-.N terms The equation is

The algorithm shown below is * suitable for 1- Start 2- Read the value of N,A 3-1=0:k=3 4- I=l+1 5- F=1; j=0 6-j=j+1 7-F=F*j 8- If j < I then goto step 6 9-S=S+(-1)^(21)*K*A*F 10- k=k+1 11- IfI < N then goto step 4 12- End S=4A+5A(2!)+ 6A(3!)+.Nterms S=4A-5A(2!)+6A(3!)-.N terms The equation is. O the equation is O S=3A+4A(2!)+ 5A(3!)+..Nterms S=-3A+4A(2!)-5A(3!)+.N terms The equation is O the equation is C S=3A-4A(2!)+5A(3!)-.N terms The equation is

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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The algorithm shown below is * suitable for ai 6 1- Start 2- Read the value of N,A 3-1=0:k=3 4-I=l+1 5- F=1; j=0 6- j=j+1 7-F=F*j 8- If j < I then goto step 6 9-S=S+(-1)^(21)*K*A *F 10-k=k+1 11- IfI < N then goto step 4 12- End S=4A+5A(2!)+ 6A(3!)+..N terms S=4A-5A(2!)+6A(3!)-....N terms The equation is. O the equation is O S=3A+4A(2!)+ 5A(3!)+...N terms S=-3A+4A(2!)-5A(3!)+..N terms The equation is O the equation is O S=3A-4A(2!)+5A(3!)-.N terms The equation is O
Transcribed Image Text:The algorithm shown below is * suitable for ai 6 1- Start 2- Read the value of N,A 3-1=0:k=3 4-I=l+1 5- F=1; j=0 6- j=j+1 7-F=F*j 8- If j < I then goto step 6 9-S=S+(-1)^(21)*K*A *F 10-k=k+1 11- IfI < N then goto step 4 12- End S=4A+5A(2!)+ 6A(3!)+..N terms S=4A-5A(2!)+6A(3!)-....N terms The equation is. O the equation is O S=3A+4A(2!)+ 5A(3!)+...N terms S=-3A+4A(2!)-5A(3!)+..N terms The equation is O the equation is O S=3A-4A(2!)+5A(3!)-.N terms The equation is O
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