Answered: The area above the x-axis and below y =…

The area above the x-axis and below y = 4- x2 The area above the x- axis and below y = 4x -x2 The area between y = sin x and the x- axis for 0 S xST

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter2: Equations And Inequalities

Section2.3: Quadratic Equations

Problem 53E

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Question

100%

Write the given (total) area as an integral.

a) the area above the x-axis and below y=4-x^2

b) The area above the x-axis and below y=4x-x^2

c) The area between y=sin x and the x-axis for 0 greater than or equal to x greater or equal

4. Evaluate the answer in a) and b).

The area above the x- axis and below y = 4 -x2 *
The area above the x- axis and below y = 4x - x2
%3D
|3D
The area between y = sin x and the x- axis for 0<xST
%3D

With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.

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