The average price of a ticket to a baseball game can be approximated by p(x) = 0.03x+0.42x+8.61, where x is the number of years after 1991 and p(x) is in dollars. a) Find p(4). b) Find p(14). p(14)-p(4) c) Find p(14)-p(4). d) Find and interpret this result. 14 -4 a) Find p(4). (Simplify your answer.) b) Find p(14). (Simplify your answer.) c) Find p(14)- p(4). (Simplify your answer.) p(14)-p(4) d) Find 14-4 (Simplify your answer.) Interpret the result. O A. It represents the average price difference of a baseball ticket from 1995 to 2005. B. The result tells us that the price of a baseball ticket in 2006 is more than in 2005. O C. It represents the average rate of change in price from 1995 to 2005. O D. It represents the price increase of baseball tickets between 1995 and 2005. Click to select your answer(s).

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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ISBN:9780079039897
Author:Carter
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Chapter9: Quadratic Functions And Equations
Section9.7: Solving Systems Of Linear And Quadratic Equations
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The average price of a ticket to a baseball game can be approximated by
p(x) = 0.03x + 0.42x+ 8.61, where x is the number of years after 1991 and p(x) is in dollars.
a) Find p(4).
b) Find p(14).
p(14)- p(4)
c) Find p(14)-p(4).
d) Find
and interpret this result.
14 -4
a) Find p(4).
(Simplify your answer.)
b) Find p(14).
(Simplify your answer.)
c) Find p(14)- p(4).
(Simplify your answer.)
p(14)– p(4)
d) Find
14-4
(Simplify your answer.)
Interpret the result.
A. It represents the average price difference of a baseball ticket from 1995 to 2005.
B. The result tells us that the price of a baseball ticket in 2006 is more than in 2005.
C. It represents the average rate of change in price from 1995 to 2005.
O D. It represents the price increase of baseball tickets between 1995 and 2005.
Click to select your answer(s).
javascript:doExercise(9);
Dro
Transcribed Image Text:The average price of a ticket to a baseball game can be approximated by p(x) = 0.03x + 0.42x+ 8.61, where x is the number of years after 1991 and p(x) is in dollars. a) Find p(4). b) Find p(14). p(14)- p(4) c) Find p(14)-p(4). d) Find and interpret this result. 14 -4 a) Find p(4). (Simplify your answer.) b) Find p(14). (Simplify your answer.) c) Find p(14)- p(4). (Simplify your answer.) p(14)– p(4) d) Find 14-4 (Simplify your answer.) Interpret the result. A. It represents the average price difference of a baseball ticket from 1995 to 2005. B. The result tells us that the price of a baseball ticket in 2006 is more than in 2005. C. It represents the average rate of change in price from 1995 to 2005. O D. It represents the price increase of baseball tickets between 1995 and 2005. Click to select your answer(s). javascript:doExercise(9); Dro
Expert Solution
Step 1 Ticket price in 1995 and 2005

It is given that, p(x)=0.03x2+0.42x+8.61

here p(x) is ticket price in dollars and x is no. of years after 1991.

 

Therefore, 

PART (a). It is given that, x=4. Therefore, 

                                                          p(4)=0.03×42+0.42×4+8.61p(4)=$10.77

so according to this average price of a ticket to a baseball game in 1995 will be $10.77.

PART (b).  It is given that, x=14. Therefore, 

                                                          p(14)=0.03×142+0.42×14+8.61p(14)=$20.37 

so according to this average price of a ticket to a baseball game in 2005 will be $20.37.

 

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