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The average value of f(x, y) over the rectangle R = {(x, y) | a ≤ x ≤ b, c ≤ y ≤d} is 1 fave = (b − a)(d—c) / f(x,y) dA. Find the average value of f(x, y) = xy² x² +1 over R = {(x, y) |0 ≤ x ≤ 1, -3 ≤ y ≤ 3}. -

The average value of f(x, y) over the rectangle R = {(x, y) | a ≤ x ≤ b, c ≤ y ≤d} is 1 fave = (b − a)(d—c) / f(x,y) dA. Find the average value of f(x, y) = xy² x² +1 over R = {(x, y) |0 ≤ x ≤ 1, -3 ≤ y ≤ 3}. -

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
ChapterA: Appendix
SectionA.2: Geometric Constructions
Problem 10P: A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in...
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6. The average value of f(x, y) over the rectangle R = {(x,y) | a ≤ x ≤ b, c≤ y ≤d} is 1 fave = (b-a)(d—c) f(x, y) dA. R Find the average value of f(x, y) = xy² x² +1 over R = {(x, y) |0 ≤ x ≤ 1, -3 ≤ y ≤ 3}.
Transcribed Image Text:6. The average value of f(x, y) over the rectangle R = {(x,y) | a ≤ x ≤ b, c≤ y ≤d} is 1 fave = (b-a)(d—c) f(x, y) dA. R Find the average value of f(x, y) = xy² x² +1 over R = {(x, y) |0 ≤ x ≤ 1, -3 ≤ y ≤ 3}.
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