The base of a cone-shaped tank is a circle of radius 5 feet, and the vertex of the cone is 12 feet above the base. The tank is filled to a depth of 7 feet, and water is flowing into the tank at a rate of 3 cubic feet per minute. Find the rate of change of the depth of the water in the tank. (v = Bh) where B is the area of the base

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 7ECP: The kinetic energy E of an object varies jointly with the object’s mass m and the square of the...
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How to find the rate of change for the following?

The base of a cone-shaped tank is a circle of radius 5 feet, and the vertex of the cone is 12
feet above the base. The tank is filled to a depth of 7 feet, and water is flowing into the tank at
a rate of 3 cubic feet per minute. Find the rate of change of the depth of the water in the tank.
(v = Bh) where B is the area of the base
Transcribed Image Text:The base of a cone-shaped tank is a circle of radius 5 feet, and the vertex of the cone is 12 feet above the base. The tank is filled to a depth of 7 feet, and water is flowing into the tank at a rate of 3 cubic feet per minute. Find the rate of change of the depth of the water in the tank. (v = Bh) where B is the area of the base
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