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The base of a three-dimensional figure is bound by the graph y = sin(x) + 1 on the interval [0, π]. Vertical cross sections that are perpendicular to the x-axis are squares. Algebraically, find the area of each square. 54 3-2-11 1 2 3 4 5 O A(x) = (sin(x) + 1) O A(x) = 2(sin(x) + 1)² ○ A(x) = —— (sin(x) + 1)² O A(x) = (sin(x) + 1)²

The base of a three-dimensional figure is bound by the graph y = sin(x) + 1 on the interval [0, π]. Vertical cross sections that are perpendicular to the x-axis are squares. Algebraically, find the area of each square. 54 3-2-11 1 2 3 4 5 O A(x) = (sin(x) + 1) O A(x) = 2(sin(x) + 1)² ○ A(x) = —— (sin(x) + 1)² O A(x) = (sin(x) + 1)²

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 67E
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The base of a three-dimensional figure is bound by the graph y = sin(x) + 1 on the interval [0, π]. Vertical cross sections that are perpendicular to the x-axis are squares. Algebraically, find the area of each square. 4 2 54-3-2-1 1 2 3 4 5 -2 A(x) = (sin(x) + 1) O_A(x) = 2(sin(x) + 1)² A(x) = —— (sin(x) + 1)² t O_A(x) = (sin(x) + 1)²
Transcribed Image Text:The base of a three-dimensional figure is bound by the graph y = sin(x) + 1 on the interval [0, π]. Vertical cross sections that are perpendicular to the x-axis are squares. Algebraically, find the area of each square. 4 2 54-3-2-1 1 2 3 4 5 -2 A(x) = (sin(x) + 1) O_A(x) = 2(sin(x) + 1)² A(x) = —— (sin(x) + 1)² t O_A(x) = (sin(x) + 1)²
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