The base of a three-dimensional figure is bound by the line y = x +2 on the interval [0, 4]. Vertical cross sections that are perpendicular to the x-axis are squares. Algebraically, find the area of each square. -2 -14 1 2 3 4 5 67 8 O A(x) = 2(x + 2)2 O A(y) = (y + 2)² O A(x) = (x+ 2)² O A(x) =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 68E
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The base of a three-dimensional figure is bound by the line y = x + 2 on the interval [0, 4]. Vertical cross sections that are perpendicular
to the x-axis are squares.
Algebraically, find the area of each square.
-2 -1,0
1234 5 678
O A(x) = 2(x + 2)²
O A(y) = (y +2)²
O A(x) = (x +2)2
O A(x) =
身
Transcribed Image Text:The base of a three-dimensional figure is bound by the line y = x + 2 on the interval [0, 4]. Vertical cross sections that are perpendicular to the x-axis are squares. Algebraically, find the area of each square. -2 -1,0 1234 5 678 O A(x) = 2(x + 2)² O A(y) = (y +2)² O A(x) = (x +2)2 O A(x) = 身
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