The base of a three-dimensional figure is bound by the line y = -x + 3 on the interval [-1, 1]. Vertical cross sections that are perpendicular to the x-axis are right triangles with a height equal to 6. Algebraically, find the area of each triangle. 3-2-1 1 2 3 4567 O A(X) = 1/1(-x+3)(6) O A(x) = 2(-x + 3)(6) O A(x) = (-x+3)(6) 1 O A(Y) 2 = (-y + 3)(6)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
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The base of a three-dimensional figure is bound by the line y = -x + 3 on the interval [-1, 1]. Vertical cross sections that are
perpendicular to the x-axis are right triangles with a height equal to 6.
Algebraically, find the area of each triangle.
Y
8
X
765
1 2 3 4 5 6 7
A(x) = 1/(-x + 3)(6)
2
A(x) = 2(-x + 3)(6)
A(x) = (-x + 3)(6)
○ A(Y) = —— (-y + 3)(6)
Transcribed Image Text:The base of a three-dimensional figure is bound by the line y = -x + 3 on the interval [-1, 1]. Vertical cross sections that are perpendicular to the x-axis are right triangles with a height equal to 6. Algebraically, find the area of each triangle. Y 8 X 765 1 2 3 4 5 6 7 A(x) = 1/(-x + 3)(6) 2 A(x) = 2(-x + 3)(6) A(x) = (-x + 3)(6) ○ A(Y) = —— (-y + 3)(6)
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